The starting team of a baseball club has 9 members who have an average of 12 home runs apiece for the season. The second-string team for the baseball club has 7 members who have an average of 9 home runs apiece for the season. What is the average number of home runs for the starting team and the second-string team combined?

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1. The starting team of a baseball club has 9 members who have an average of 12 home runs apiece for the season. The second-string team for the baseball club has 7 members who have an average of 9 home runs apiece for the season. What is the average number of home runs for the starting team and the second-string team combined?

9 sides, This can be split into 7 triangles, so 180 x 7 = 1260
First there are a total of 11 balls. 5/11 are not green while 6/11 are green. So, 5/11 x 100 (part/whole) x 100 is .45% or 45%. A shortcut for this problem would be to look at the probability. 5/11 is roughly around 50%, but we know it is just under it. So, many of the choices could be eliminated right off the bat.
3 x 5 x 2= 30 (Multiply all number since there is only one of each). Use slot method. _ _ _=
First, we want to find the total number of runs for each team. First the first team it should equal 108 (9 x 12= 108). The second team should it equal 56 (7 x 8= 56). Add both of these totals, and you should get 164. Since there are a total of 16 members (9 + 7= 16), dived 164 by 16 and you should get 10.25.

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