Calculate the emf for a cell operating with the following reaction:Cr2O72-(aq) + 6 I-(aq) + 14 H+(aq) → 2 Cr3+(aq) + 3 I2(s) + 7 H2O(l),where [Cr2O72-] = 0.020 M, [I-] = 0.015 M, [Cr3+] = 0.20 M and [H+] = 0.50 M, using the following standard reduction potentials:Cr2O72-(aq) + 14 H+(aq) + 6 e- → 2 Cr3+(aq) + 7 H2O(l) E° = +1.33 VI2(s) + 2 e- → 2 I-(aq) E° = +0.54 V

🎲 Try a Random Question  |  Total Questions in Quiz: 99  |  🧠 Study this quiz with Flashcards
This question is part of a full practice quiz:
CHEM102 Final Exam - General Chemistry II — practice the complete quiz, review flashcards, or try a random question.

MCQS on the chemical principles and theories that are used in a variety of practical applications. Topics include chemical kinetics, solution chemistry, chemical equilibrium, acids, bases, and buffers, electrochemistry, nuclear chemistry, and an introduction to organic chemistry.


Calculate the emf for a cell operating with the following reaction:<br/>Cr<sub>2</sub>O<sub>7</sub><sup>2-</sup>(aq) + 6 I<sup>-</sup>(aq) + 14 H<sup>+</sup>(aq) → 2 Cr<sup>3+</sup>(aq) + 3 I<sub>2</sub>(s) + 7 H<sub>2</sub>O(l),<br/>where [Cr<sub>2</sub>O<sub>7</sub><sup>2-</sup>] = 0.020 M, [I<sup>-</sup>] = 0.015 M, [Cr<sup>3+</sup>] = 0.20 M and [H<sup>+</sup>] = 0.50 M, using the following standard reduction potentials:<br/>Cr<sub>2</sub>O<sub>7</sub><sup>2-</sup>(aq) + 14 H<sup>+</sup>(aq) + 6 e<sup>-</sup> → 2 Cr<sup>3+</sup>(aq) + 7 H<sub>2</sub>O(l) E° = +1.33 V<br/>I<sub>2</sub>(s) + 2 e<sup>-</sup> → 2 I<sup>-</sup>(aq) E° = +0.54 V<br/>