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A particle moves in a straight line and its velocity v at time t seconds is given byv = 3t2 – 4t + 5 cm/second. What will be the distance travelled by the particle during first 3 seconds after the start?

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Related Test: Class 12 Maths Practice Test - Calculus Application - Acceleration


A particle moves in a straight line and its velocity v at time t seconds is given byv = 3t<sup>2</sup> – 4t + 5 cm/second. What will be the distance travelled by the particle during first 3 seconds after the start?






 
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