Inertia Forces in Reciprocating Parts topics include: Kliens, bennetts and ritterhaus construction, velocity and acceleration of engines, reciprocating parts of engines. Inertia forces in reciprocating parts are caused by the oscillation of reciprocating masses. These forces act along the line of stroke and through the cross head on the structures and on the main bearing of the crankshaft.  The inertia force due to the acceleration of the reciprocating parts opposes the force on the piston. The inertia force due to retardation of the reciprocating parts helps the force on the piston.  The... Show more

Inertia Forces in Reciprocating Parts topics include: Kliens, bennetts and ritterhaus construction, velocity and acceleration of engines, reciprocating parts of engines.

Inertia forces in reciprocating parts are caused by the oscillation of reciprocating masses. These forces act along the line of stroke and through the cross head on the structures and on the main bearing of the crankshaft. 

The inertia force due to the acceleration of the reciprocating parts opposes the force on the piston. The inertia force due to retardation of the reciprocating parts helps the force on the piston. 
The inertial force of mass can be calculated by multiplying the object's mass by its acceleration. 
Balancing is a method of correcting or eliminating unwanted inertia forces and couples in rotating and reciprocating parts of the machine.

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Machine Dynamics Practice Test: Inertia Forces in Reciprocating Parts

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25 Questions

1. From figure, acceleration of P with respect to C is given by_________

ω2.OMω2.QNω2.CNω2.PC

2. If OC is the crank and PC is the connecting rod rotating in clockwise direction in the figure given below, then triangle OCM is known as _________

Klein’s velocity diagramBennett’ acceleration diagramKlein’s acceleration diagramBennett’ velocity diagram

3. When the piston is accelerated, the piston effort is given by which of the following the equation?

F(L) – F(I) + R(f)F(L) + F(I)F(L) ± F(I)F(L) – F(I)

4. Ritterhaus’ construction is used when the motion of the crank is linear shm.

FalseDon't KnowMaybeTrue

5. Klein’s constructions can be used to determine the acceleration of various parts at all locations.

FalseDon't KnowMaybeTrue

6. The crank and connecting rod of a steam engine are 0.3 m and 1.5 m in length. The crank rotates at 150 r.p.m. clockwise, determine velocity of the piston when the crank is at an angle 40 degrees from IDC.

53.364.193.49

7. Which of the following is incorrect regarding inertia force?

Brings the body to equilibriumSame direction as of accelerating forceImaginary forceActs upon a rigid body

8. With respect to the figure given quadrilateral CQNO is known as _______

Klein’s displacement diagramKlein’s velocity diagramBennet’s diagramKlein’s acceleration diagram

9. Considering a four bar chain with each link having linear and angular acceleration, applying D-Alembert’s principle will never result in which of the following member?

2- force memberNon accelerating member4 – force member3- force member

10. From figure, what is the absolute velocity of P, i.e velocity of P with respect to the stationary point O?

ω × OMω × CMω × QNω × OC

11. From figure, what is the absolute velocity of P, i.e velocity of P with respect to the stationary point O?

ω × OCω × OMω × CMω × QN

12. A Piston will remain in equilibrium if ________

Inertia force is applied in the direction Parallel to the resultant forceInertia force is applied in the direction opposite to the resultant forceInertia force is applied in the same direction to the resultant forceInertia force is applied in the direction Perpendicular to the resultant force

13. In given figure, Triangle OCM is known as ________

Klein’s velocity diagramBennet’s diagramKlein’s acceleration diagramKlein’s displacement diagram

14. The crank-pin circle radius of a horizontal engine is 300 mm. The mass of the reciprocating parts is 250 kg. When the crank has travelled 30° from T.D.C., the difference between the driving and the back pressures is 0.45 N/mm². The connecting rod length between centres is 1.2 m and the cylinder bore is 0.5 m. If the engine runs at 250 r.p.m. and if the effect of piston rod diameter is neglected, calculate the net load on piston.

90560 N88357 N88000 N78036 N

15. Acceleration of any point D on the connecting rod is given by ________

ω2.OD2ω2.PDω2.ODω2.OD1

16. In the given figure, the velocity of piston is maximum under which of the following conditions?

N lies to the right of ON lies above ON lies to the left of ON coincides with O

17. Which of the following construction methods is not used to calculate the velocity and acceleration of reciprocating parts of the internal combustion engine?

Bennett’s constructionRitterhaus’s constructionD-Alembert’s constructionsKlien’s construction

18. In the presence of frictional resistance, the expression for piston effort is _________

F(L) – F(I) + R(f)F(L) ± F(I) – R(f)F(L) – F(I)F(L) + F(I)

19. Crank effort is the product of crank pin radius and _______

Thrust on sidesCrankpin effortForce acting along connecting rodPiston effort

20. Inertia torque acts in the same direction as the accelerating couple?

TrueMaybeDon't KnowFalse

21. From figure, what is the velocity of P with respect to C?

ω × OCω × OMω × QNω × CM

22. For the given data of an Internal combustion engine : Mass of parts = 180 kg bore = 175 mm, length of stroke = 200 mm, engine speed = 500 r.p.m., length of connecting rod = 400 mm and crank angle = 60° from T.D.C, find the inertia force.

17.56 N18.00 N18.53 N19.2 N

23. In which of the following cases Klein’s construction can be used?

Crank has a uniform angular accelerationWhen the motion is SHMCrank has a uniform angular velocityLever has a uniform angular acceleration

24. From the data given:
The length of the crank and connecting rod are 150 mm and 600 mm
The crank position is 60° from inner dead centre. The crank shaft speed is 400 r.p.m.
Find the angular acceleration in rad/s² of the connecting rod.

421379400388

25. Why the inertia torque acts in the opposite direction to the accelerating couple?

To reduce the accelerating torqueActs as a constraint torqueIncrease the linear accelerationBring the body in equilibrium