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It is predicted that the cooling of a steel part under the influence of forced convection will follow the differential equation dT/dt = -0.03 (T-22)1.8, where t is in minutes and T is in degrees C. At t = 0, T = 500 degrees C. Use the Runge-Kutta method (2nd order with direct analytical evaluation of the second derivative) with a time step (h) of 0.22 minutes to predict the temperature of the part in degrees C at t = 5 minutes.

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It is predicted that the cooling of a steel part under the influence of forced convection will follow the differential equation dT/dt = -0.03 (T-22)<sup>1.8</sup>, where t is in minutes and T is in degrees C. <br/><br/>At t = 0, T = 500 degrees C. <br/><br/>Use the Runge-Kutta method (2nd order with direct analytical evaluation of the second derivative) with a time step (h) of 0.22 minutes to predict the temperature of the part in degrees C at t = 5 minutes.






 
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