The data in the table below indicate one spatial coordinate of an incoming missile as a function of time. We wish to estimate the value of the spatial coordinate at intermediate times by quadratic interpolation.Time (ms)Position (m)050852005245400530160054908005605You need to estimate the position at t = 500 ms. First, fit a quadratic to the positions at 0, 200, and 400 ms. Then, fit a second quadratic to the data at 400 and 600 ms with the additional constraint that the slopes of the first and second quadratics are the same at t = 400 ms. The first quadratic, that fits the first three positions, is x(t) = 5085 + 1.06t - 0.0013 t2 (where x is in meters and t is in milliseconds). Find the second quadratic and estimate the position at t = 500 ms. Which of the following positions best matches the position predicted by your second quadratic for t = 500 ms?

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The data in the table below indicate one spatial coordinate of an incoming missile as a function of time. We wish to estimate the value of the spatial coordinate at intermediate times by quadratic interpolation.<table border='1' align='middle''font-family:'lucida grande', tahoma, verdana, arial, sans-serif;font-size:11px;font-style:inherit;font-variant:inherit;border-spacing:0px;border-collapse:collapse;font-weight:inherit;direction:ltr;text-align:left;color:rgb(51, 51, 51);width:238px;height:172px;'><tbody><tr><td width='50%' valign='top' >Time (ms)<br/></td><td width='50%' valign='top' >Position (m)<br/></td></tr><tr><td width='50%' valign='top' >0<br/></td><td width='50%' valign='top' >5085<br/></td></tr><tr><td width='50%' valign='top' >200<br/></td><td width='50%' valign='top' >5245<br/></td></tr><tr><td width='50%' valign='top' >400<br/></td><td width='50%' valign='top' >5301<br/></td></tr><tr><td width='50%' valign='top' >600<br/></td><td width='50%' valign='top' >5490<br/></td></tr><tr><td width='50%' valign='top' >800<br/></td><td width='50%' valign='top' >5605<br/></td></tr></tbody></table><br/>You need to estimate the position at t = 500 ms. <br/><br/>First, fit a quadratic to the positions at 0, 200, and 400 ms. Then, fit a second quadratic to the data at 400 and 600 ms with the additional constraint that the slopes of the first and second quadratics are the same at t = 400 ms. <br/><br/>The first quadratic, that fits the first three positions, is x(t) = 5085 + 1.06t - 0.0013 t<sup>2</sup> (where x is in meters and t is in milliseconds). <br/><br/>Find the second quadratic and estimate the position at t = 500 ms. <br/><br/>Which of the following positions best matches the position predicted by your second quadratic for t = 500 ms?