In an electrochemical machining operation, the frontal working area of the electrode is 2.5 in2. The applied current = 1500 amps, and the voltage = 12 volts. The material being cut is pure aluminium, whose specific removal rate C = 0.000126 in3/A-min. If the resistivity of the electrolyte = 6.2 ohm-in, what is the working gap?

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In an electrochemical machining operation, the frontal working area of the electrode is 2.5 in2. The applied current = 1500 amps, and the voltage = 12 volts. The material being cut is pure aluminium, whose specific removal rate C = 0.000126 in3/A-min. If the resistivity of the electrolyte = 6.2 ohm-in, what is the working gap?