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Alkyne reactions involve the addition of various reagents to the triple bond in alkynes, the acidity of terminal alkynes, and alkylation processes. This topic appears in exams because it tests your understanding of organic chemistry principles, reaction mechanisms, and the properties of alkynes. Questions typically involve identifying products of reactions, predicting reaction outcomes, and understanding the acidity of terminal alkynes.
This topic is tested in organic chemistry exams, particularly in undergraduate and graduate-level courses. It frequently appears in midterm and final exams, carrying moderate to high marks. It tests your ability to apply reaction mechanisms, understand chemical properties, and predict reaction outcomes.
Without these prerequisites, you may struggle with identifying reagents, predicting products, and understanding the mechanisms involved.
Intermediate
Question: What is the product of the reaction between acetylene (HC≡CH) and bromine (Br₂)? Step-by-Step: 1. Identify the reagents: Acetylene (HC≡CH) and bromine (Br₂).2. Recognize the addition reaction: Br₂ adds across the triple bond.3. Form the product: 1,2-dibromoethene (BrHC=CHBr).Answer: 1,2-dibromoethene.Rule Applied: Halogenation of alkynes.
Question: What is the product of the reaction between propyne (CH₃C≡CH) and hydrogen chloride (HCl)? Step-by-Step: 1. Identify the reagents: Propyne (CH₃C≡CH) and hydrogen chloride (HCl).2. Recognize the addition reaction: HCl adds across the triple bond.3. Form the product: 2-chloropropene (CH₃CCl=CH₂).Answer: 2-chloropropene.Rule Applied: Hydrohalogenation of alkynes.
Question: What is the product of the reaction between acetylene (HC≡CH), sodium amide (NaNH₂), and methyl iodide (CH₃I)? Step-by-Step: 1. Identify the reagents: Acetylene (HC≡CH), sodium amide (NaNH₂), and methyl iodide (CH₃I).2. Deprotonation: Acetylene reacts with NaNH₂ to form the acetylide anion (HC≡C⁻).3. Alkylation: Acetylide anion reacts with CH₃I to form propyne (CH₃C≡CH).Answer: Propyne.Rule Applied: Alkylation of terminal alkynes.
Question: What is the product of the reaction between acetylene (HC≡CH) and hydrogen (H₂) in the presence of a palladium catalyst? Options: A) Ethane B) Ethene C) Ethyne D) Ethanol Correct Answer: A) Ethane Explanation: Hydrogenation of acetylene forms ethane.Why the Distractors Are Tempting: - B) Ethene: Confusion with partial hydrogenation.- C) Ethyne: Confusion with the starting material.- D) Ethanol: Confusion with hydration products.
Question: What is the product of the reaction between propyne (CH₃C≡CH) and bromine (Br₂)? Options: A) 1-bromopropene B) 1,2-dibromopropene C) 2,3-dibromopropene D) 1,1-dibromopropene Correct Answer: C) 2,3-dibromopropene Explanation: Halogenation of propyne forms 2,3-dibromopropene.Why the Distractors Are Tempting: - A) 1-bromopropene: Confusion with monosubstitution.- B) 1,2-dibromopropene: Incorrect regioselectivity.- D) 1,1-dibromopropene: Incorrect addition pattern.
Question: What is the product of the reaction between acetylene (HC≡CH), sodium amide (NaNH₂), and ethyl iodide (C₂H₅I)? Options: A) Butyne B) Propyne C) Ethyne D) Ethane Correct Answer: A) Butyne Explanation: Alkylation of acetylene forms butyne.Why the Distractors Are Tempting: - B) Propyne: Confusion with partial alkylation.- C) Ethyne: Confusion with the starting material.- D) Ethane: Confusion with hydrogenation products.
Question: Which of the following is the correct order of acidity? Options: A) Ethane < Ethyne < Ethene B) Ethyne < Ethane < Ethene C) Ethene < Ethane < Ethyne D) Ethane < Ethene < Ethyne Correct Answer: D) Ethane < Ethene < Ethyne Explanation: Terminal alkynes are more acidic than alkenes and alkanes.Why the Distractors Are Tempting: - A) Ethane < Ethyne < Ethene: Incorrect order of acidity.- B) Ethyne < Ethane < Ethene: Incorrect order of acidity.- C) Ethene < Ethane < Ethyne: Incorrect order of acidity.
Question: What is the product of the reaction between 2-butyne (CH₃C≡CCH₃) and hydrogen chloride (HCl)? Options: A) 2-chloro-2-butene B) 2-chlorobutane C) 2,3-dichlorobutane D) 2-chloro-1-butene Correct Answer: A) 2-chloro-2-butene Explanation: Hydrohalogenation of 2-butyne forms 2-chloro-2-butene.Why the Distractors Are Tempting: - B) 2-chlorobutane: Confusion with saturated products.- C) 2,3-dichlorobutane: Incorrect addition pattern.- D) 2-chloro-1-butene: Incorrect regioselectivity.
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