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A system of linear equations is a set of two or more equations that contain two or more variables. Solving systems of linear equations using substitution and elimination methods is a fundamental concept in algebra that allows us to find the values of the variables that satisfy all the equations in the system.
Solving systems of linear equations is crucial in various fields, including economics, engineering, and data analysis. For instance, in economics, systems of linear equations can be used to model the relationships between different economic variables, such as supply and demand. In engineering, systems of linear equations can be used to design and optimize systems, such as electrical circuits and mechanical systems. In data analysis, systems of linear equations can be used to model the relationships between different variables in a dataset.
Solve the system of linear equations {2x + 3y = 5, 4x - 2y = 3} using the substitution method.
$$\begin{aligned} \text{Step 1: Solve the first equation for x.}\ 2x + 3y &= 5\ 2x &= 5 - 3y\ x &= \frac{5 - 3y}{2}\ \end{aligned}$$
$$\begin{aligned} \text{Step 2: Substitute the result into the second equation.}\ 4\left(\frac{5 - 3y}{2}\right) - 2y &= 3\ 10 - 6y - 2y &= 3\ -8y &= -7\ y &= \frac{7}{8}\ \end{aligned}$$
$$\begin{aligned} \text{Step 3: Substitute the value of y back into the first equation to find the value of x.}\ 2x + 3\left(\frac{7}{8}\right) &= 5\ 2x + \frac{21}{8} &= 5\ 2x &= 5 - \frac{21}{8}\ 2x &= \frac{40 - 21}{8}\ 2x &= \frac{19}{8}\ x &= \frac{19}{16}\ \end{aligned}$$
Solve the system of linear equations {x + 2y = 4, 3x - 2y = 5} using the elimination method.
$$\begin{aligned} \text{Step 1: Multiply the first equation by 3 and the second equation by 1 to make the coefficients of x in both equations equal.}\ 3(x + 2y) &= 3(4)\ 3x + 6y &= 12\ 3x - 2y &= 5\ \end{aligned}$$
$$\begin{aligned} \text{Step 2: Add the two equations to eliminate the x-variable.}\ (3x + 6y) + (3x - 2y) &= 12 + 5\ 6x + 4y &= 17\ \end{aligned}$$
$$\begin{aligned} \text{Step 3: Solve the resulting equation for y.}\ 4y &= 17 - 6x\ y &= \frac{17 - 6x}{4}\ \end{aligned}$$
$$\begin{aligned} \text{Step 4: Substitute the value of y back into one of the original equations to find the value of x.}\ x + 2\left(\frac{17 - 6x}{4}\right) &= 4\ x + \frac{17 - 6x}{2} &= 4\ 2x + 17 - 6x &= 8\ -4x &= -9\ x &= \frac{9}{4}\ \end{aligned}$$
Solve the system of linear equations {x - 2y = 3, 2x + 3y = 5} using the elimination method.
$$\begin{aligned} \text{Step 1: Multiply the first equation by 2 and the second equation by 1 to make the coefficients of x in both equations equal.}\ 2(x - 2y) &= 2(3)\ 2x - 4y &= 6\ 2x + 3y &= 5\ \end{aligned}$$
$$\begin{aligned} \text{Step 2: Subtract the second equation from the first equation to eliminate the x-variable.}\ (2x - 4y) - (2x + 3y) &= 6 - 5\ -7y &= 1\ y &= -\frac{1}{7}\ \end{aligned}$$
$$\begin{aligned} \text{Step 3: Substitute the value of y back into one of the original equations to find the value of x.}\ x - 2\left(-\frac{1}{7}\right) &= 3\ x + \frac{2}{7} &= 3\ x &= 3 - \frac{2}{7}\ x &= \frac{21 - 2}{7}\ x &= \frac{19}{7}\ \end{aligned}$$
What is the correct method for solving the system of linear equations {2x + 3y = 5, 4x - 2y = 3}?
A) Substitution method B) Elimination method C) Graphing method D) Matrix method
What is the correct solution to the system of linear equations {x + 2y = 4, 3x - 2y = 5}?
A) x = 3, y = 1 B) x = 2, y = 1 C) x = 3, y = -1 D) x = 2, y = -1
What is the correct method for solving the system of linear equations {x - 2y = 3, 2x + 3y = 5}?
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