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1. Fill in the blanks: (a) 1 lakh = _______________ ten thousand (b) 1 million = _______________ hundred thousand (c) 1 crore = _______________ ten lakh (d) 1 crore = _______________ million (e) 1 million = _______________ lakh.
2. Place commas correctly and write the numerals:
(a) Seventry-three lakh seventy-five thousand three hundred seven. (b) Nine crore five lakh forty-one. (c) Seven crore fifty-two lakh twenty-one thousand three hundred two. (d) Fifty-eight million four hundred twenty-three thousand two hundred two. (e) Twenty-three lakh thirty thousand ten.
3. Insert commas suitable and write the names according to Indian system of numeration: (a) 87595762 (b) 8546283 (c) 99900046 (d) 9843270.
4. Insert commas suitable and write the names according to International system of numeration: (a) 78921092 (b) 7452283 (c) 99985102 (d) 4804983.
Answers:
1. (a) 10 (b) 10 (c) 10 (d) 1 (e) 10
2. (a) 73,75,307 (c) 7,52,21,302 (e) 23,30,010 (b) 9,05,00,041 (d) 58,423,20. 3. (a) 8,75,95,762 → Eight crore seventy-five lakh ninety-five thousand seven hundred sixty-two (b) 85,46,283 → Eight-five lakh forty-six thousand two hundred eighty-three (c) 9,99,00,046 → Nine crore ninety-nine lakh forty-six (d ) 9,84,32,701 → Nine crore eighty-four lakh thirty-two thousand seven hundred on. 4. (a) 78,921,092 → Seventy-eight million nine hundred twenty-one thousand ninety-two (b) 7,452,483 → Seven million four hundred fifty-two thousand two hundred eighty-three (c) 99,985,102 → Ninety-nine million nine hundred eighty-five thousand one hundred two (d) 48,049,831 → Forty-eight million forty-nine thousand eight hundred thirty-on.
............................................................................................................................................................. Question.
1. A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094, 1812, 2050 and 2751. Find the total number of tickets sold on all the four days.2. Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10,000 runs. How many more runs does he need?3. In an election, the successful candidate registered 5,77,500 votes and his nearest rival secured 3,48,700 votes. By what margin did the successful candidate win the election?4. Kirti Bookstore sold books worth ` 2,85,891 in the first week of June and books worth ` 4,00,768 in the second week o the month. How much was the sale for the two weeks together? In which week was the sale greater and by how much?5. Find the difference between the greatest and the least number that can be written using the digits 6, 2, 7, 4, 3 each only once.6. A machine, on an average, manufactures 2,825 screws a day. How many screws did it produce in the month of January 2006?7. A merchant had ` 78,592 with her. She placed an order for purchasing 40 radio sets at ` 1,200 each. How much money will remain with her after the purchase?8. A student multiplied 7236 by 65 instead of multiplying by 56. By how much was his answer greater than the correct answer?9. To stitch a shirt 2 m 15 cm cloth is needed. Out of 40 m cloth, how many shirts can be stitched and how much cloth will remain?10. Medicine is packed in boxes, each weighing 4 kg 500 g. How many such boxes can be loaded in a can which cannot carry beyond 800 kg?11. The distance between the school and the house of a student’s house is 1 km 875 m. Everyday she walks both ways. Find the total distance covered by her in six days.12. A vessel has 4 liters and 500 ml of curd. In how many glasses each of 25 ml capacity, can it be filled.
1. Number of tickets sold on first day = 1,094 Number of tickets sold on second day = 1,812 Number of tickets sold on third day = 2,050 Number of tickets sold on fourth day = + 2,751 Total tickets sold = 7,707 Therefore, 7,707 tickets were sold on all the four days.
2. Runs to achieve Runs scored Runs required Therefore, he needs 3,020 more runs.
3. Number of votes secured by successful candidates = 5,77,500 Number of votes secured by his nearest rival = – 3,48,700 Margin between them = 2,28,800 Therefore, the successful candidate won by a margin of 2,28,800 votes.
4. Books sold in first week = 2,85,891 Books sold in second week = + 4,00,768 Total books sold = 6,86,659 Since, 4,00,768,> 2,85,891 Therefore sale of second week is greater than that of first week. Books sold in second week = 4,00,768 Books sold in first week = – 2,85,891 More books sold in second week = 1,14,877 Therefore, 1,14,877 more books were sold in second week.
5. Greatest five-digit number using digits 6,2,7,4,3 Smallest five-digit number using digits 6,2,7,4,3 Difference Therefore the difference is 52965.
6. Number of screws manufactured in one day Number of days in the month of January (31 days. = 10,000 = – 6,980 = 3,02. = 76432 = – 23467 = 5296. = 2,825 = 2,825 x 31 = 87,575 Therefore the machine produced 87,575 screws in the month of January.
7. Cost of one radio = ` 1200 Cost of 40 radios = 1200 x 40 = ` 48,000 Now, Total money with merchant = ` 78,592 Money spent by her = – ` 48,000 Money left with her = ` 30,592 Therefore, ` 30,592 will remain with her after the purchase.
8. Wrong answer = 7236 x 65 7236 x 65 36180 43416 x47034. Correct answer = 7236 x 56 7236 x 56 43416 36180 x40521. Difference in answers = 470340 – 405216 = 65,124
9. Cloth required to stitch one shir. = 2 m 15 cm = 2 x 100 cm + 15 cm = 215 cm Length of cloth = 40 m = 40 x 100 cm = 4000 cm Number of shirts can be stitched = 4000 ÷ 215 18 215 4000 − 215 1850 −1720 130 Therefore, 18 shirts can be stitched and 130 cm (1 m 30 cm) cloth will remain.
10. The weight of one box = 4 kg 500 g = 4 x 1000 g + 500 g = 4500 g Maximum load can be loaded in van = 800 kg = 800 x 1000 g = 800000 g Number of boxes = 800000 ÷ 450. 177 4500 800000 − 4500 35000 −31500 35000 −31500350. Therefore, 177 boxes can be loaded.
11. Distance between school and home = 1.875 km Distance between home and school = + 1.875 km Total distance covered in one day = 3.750 km Distance covered in six days = 3.750 x 6 = 22.500 km Therefore, 22 km 500 m distance covered in six days.
12. Capacity of curd in a vessel = 4 liters 500 ml = 4 x 1000 ml + 500 ml = 4500 ml Capacity of one glass = 25 ml Number of glasses can be filled = 4500 ÷ 25 180 25 4500 − 25 200 −200 0 Therefore, 180 glasses can be filled by curd.
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1. Estimate each of the following using general rule: (a) 730 + 998 (b) 796 – 314 (c) 12,904 + 2,888 (d) 28,292 – 21,49.
2. Give a rough estimate (by rounding off to nearest hundreds) and also a closer estimate (by rounding off to nearest tens): (a) 439 + 334 + 4317 (b) 1,08,737 – 47,599 (c) 8325 – 491 (d) 4,89,348 – 48,36.
3. Estimate the following products using general rule: (a) 578 x 161 (b) 5281 x 3491 (c) 1291 x 592 (d) 9250 x 2.
Answers:.
1.
(a) 730 round off to 700 998 round off to 1000 Estimated sum = 1700
(b) 796 round off to 800 314 round off to 300 Estimated sum = 500
(c) 12904 round off to 13000 2888 round off to 3000 Estimated sum = 1600.
(d) 28292 round off to 21496 round off to Estimated difference. 28000 21000 7000 2.
(a) 439 round off to 400 334 round off to 300 4317 round off to 4300 Estimated sum = 5000
(b) 108734 round off to 47599 round off to Estimated difference . 108700 47600 61100
(c) 8325 round off to 8300 491 round off to 500 Estimated difference = 7800 (d) 489348 round off to 48365 round off to Estimated difference . 489300 48400 440900
3.
(a) 578 x 161 578 round off to 600 161 round off to 200 The estimated product = 600 x 200 = 1,20,000
(b) 5281 x 3491 5281 round of to 5,000 3491 round off to 3,500 The estimated product = 5,000 x 3,500 = 1,75,00,000
(c) 1291 x 592 1291 round off to 1300 592 round off to 600 The estimated product = 1300 x 600 = 7,80,000
(d) 9250 x 29 9250 round off to 10,000 229 round off to 30 The estimated product = 10,000 x 30 = 3,00,00.
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