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Intermediate — requires visualization of 3D geometries and understanding of hybridisation-electron domain relationship, but core principles are straightforward and formula-based.
Trap: Assuming molecular geometry is same as electron pair geometry. Avoid: Always check for lone pairs; e.g., NH₃ is trigonal pyramidal (molecular), not tetrahedral (electron geometry).
Trap: Assigning hybridisation based on number of atoms bonded, not electron domains. Avoid: Count total electron pairs (bond pairs + lone pairs); e.g., SO₂ has three electron domains → sp², not sp.
Trap: Thinking sp³d hybridisation implies d-orbital participation in main group elements. Avoid: Hybridisation is a model; d-orbitals in PCl₅ or SF₆ are not significantly involved; focus on geometry and electron domains as per NCERT.
Q1. Which of the following species has a linear shape and sp hybridisation? A) H₂O B) NH₃ C) CO₂ D) SO₂
Answer: C Explanation: CO₂ has two bond pairs, no lone pairs on C, linear shape, and sp hybridisation. Why others fail: SO₂ has bent shape and sp² hybridisation due to lone pair on S.
Q2. What is the molecular geometry of XeF₂? A) Linear B) Bent C) Trigonal planar D) Trigonal bipyramidal
Answer: A Explanation: XeF₂ has three lone pairs and two bond pairs; electron geometry trigonal bipyramidal, molecular geometry linear. Why others fail: Students confuse electron geometry (trigonal bipyramidal) with molecular geometry.
Q3. The hybridisation of phosphorus in PCl₅ is: A) sp³ B) sp³d C) sp³d² D) dsp²
Answer: B Explanation: PCl₅ has five electron domains, requiring sp³d hybridisation for trigonal bipyramidal geometry. Why others fail: sp³d² is for six domains (e.g., SF₆); students miscount electron pairs.
Q4. Which molecule has the smallest bond angle? A) CH₄ B) NH₃ C) H₂O D) BF₃
Answer: C Explanation: H₂O has two lone pairs causing maximum repulsion, reducing bond angle to 104.5°. Why others fail: NH₃ (107°) is close, but H₂O has smaller angle due to two lone pairs.
Q5. The correct order of hybridisation of carbon atoms in CH₃–CH=CH–CN is: A) sp³, sp², sp², sp B) sp³, sp, sp, sp C) sp³, sp², sp, sp D) sp³, sp², sp², sp²
Answer: A Explanation: CH₃– (sp³), –CH= (sp²), =CH– (sp²), –CN (sp); triple bond carbon is sp hybridised. Why others fail: Students misassign hybridisation of nitrile carbon (sp, not sp²).
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