By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Q: What is the structural difference between ATP and ADP? A: ATP has three phosphate groups (triphosphate), while ADP has two (diphosphate); the third phosphate bond in ATP stores high-energy electrons. Trap/Clarification: The bond itself isn’t "high-energy"—the hydrolysis of the terminal phosphate releases energy due to electrostatic repulsion and resonance stabilization of products.
Q: What is a phosphorylated intermediate? A: A molecule (e.g., glucose-6-phosphate) that has received a phosphate group from ATP, becoming more reactive and primed for subsequent metabolic steps. Trap/Clarification: Phosphorylation does not always activate a molecule; it can also inhibit (e.g., glycogen synthase is inactivated by phosphorylation).
Q: Why is ATP hydrolysis exergonic? A: The products (ADP + Pi) are more stable than ATP due to reduced electrostatic repulsion between negatively charged phosphates and increased resonance stabilization of the inorganic phosphate. Trap/Clarification: The ?G of ATP hydrolysis is context-dependent (e.g., -7.3 kcal/mol in standard conditions, but can exceed -13 kcal/mol in cells due to low [ADP] and [Pi]).
Q: Why is energy coupling essential for cellular work? A: Most cellular processes (e.g., protein synthesis, ion transport) are endergonic (?G > 0) and cannot proceed spontaneously; ATP hydrolysis provides the necessary free energy to drive these reactions. Trap/Clarification: Coupling requires a shared intermediate (e.g., phosphorylated substrate) or enzyme (e.g., kinase); simply mixing ATP with a reaction won’t work.
Q: How does ATP power active transport (e.g., Na?/K? pump)? A: ATP phosphorylates the pump protein, inducing a conformational change that translocates ions against their gradients; dephosphorylation resets the pump. Trap/Clarification: The pump hydrolyzes ATP (ATP-ADP + Pi), but the energy comes from the phosphorylation step, not the hydrolysis itself.
Q: How is the efficiency of ATP coupling calculated? A: Efficiency = (Energy captured in useful work / Energy released by ATP hydrolysis) × 100%; e.g., if a reaction requires +5 kcal/mol and ATP provides -7.3 kcal/mol, efficiency-68%. Trap/Clarification: Efficiency is never 100%—some energy is always lost as heat (2nd Law of Thermodynamics).
Q: Can ATP be synthesized without a proton gradient? A: Yes, via substrate-level phosphorylation (e.g., in glycolysis or the Krebs cycle), where a phosphorylated substrate directly donates Pi to ADP. Trap/Clarification: Substrate-level phosphorylation does not require oxygen or membranes, unlike oxidative phosphorylation.
Q: Under what conditions does ATP hydrolysis become more exergonic? A: When cellular [ADP] and [Pi] are low (e.g., during high metabolic demand), shifting the equilibrium toward ATP hydrolysis and increasing the magnitude of ?G. Trap/Clarification: The ?G of ATP hydrolysis is not fixed—it’s a function of the mass-action ratio ([ADP][Pi]/[ATP]).
Statement: The terminal phosphate bond in ATP is the strongest bond in the molecule. Answer: FALSE Why the common mistake happens: Students confuse "high-energy" with bond strength; the terminal bond is weak (easily hydrolyzed) due to repulsion between negative charges.
Statement: Substrate-level phosphorylation occurs in the mitochondrial matrix during oxidative phosphorylation. Answer: FALSE Why the common mistake happens: Students conflate substrate-level phosphorylation (e.g., Krebs cycle) with oxidative phosphorylation (ETC + ATP synthase), which are distinct processes.
Statement: A reaction with ?G = +4 kcal/mol can be driven by coupling to ATP hydrolysis (?G = -7.3 kcal/mol). Answer: TRUE Why the common mistake happens: Students forget that coupling requires the net ?G to be negative; here, -7.3 + 4 = -3.3 kcal/mol (spontaneous).
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