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Logarithmic Differentiation is a technique used to differentiate functions that are products, quotients, or powers, by first taking the natural logarithm of both sides of the equation. This topic appears in exams because it tests your ability to handle complex differentiation problems efficiently. Typical questions involve differentiating functions that are difficult to handle with standard differentiation rules.
Logarithmic Differentiation is tested in calculus exams, particularly in AP Calculus, university-level calculus courses, and some engineering and science entrance exams. It frequently appears in differentiation sections, carrying moderate to high marks. This skill tests your understanding of logarithms, differentiation rules, and algebraic manipulation.
ln(x)
e^x
x
If these prerequisites are missing, you will struggle with logarithmic differentiation, leading to incorrect applications of differentiation rules and algebraic errors.
To differentiate a function y = f(x) using logarithmic differentiation: 1. Take the natural logarithm of both sides: ln(y) = ln(f(x)).2. Differentiate both sides with respect to x.3. Solve for dy/dx.
y = f(x)
ln(y) = ln(f(x))
dy/dx
Think of logarithmic differentiation as a three-step process: Log, Differentiate, Solve.
Intermediate
d/dx [f(g(x))] = f'(g(x)) * g'(x)
d/dx [f(x)g(x)] = f'(x)g(x) + f(x)g'(x)
d/dx [f(x)/g(x)] = [f'(x)g(x) - f(x)g'(x)] / [g(x)]^2
Question: Differentiate y = x^2 * e^x using logarithmic differentiation.
y = x^2 * e^x
ln(y) = ln(x^2 * e^x)
ln(y) = ln(x^2) + ln(e^x) = 2ln(x) + x
1/y * dy/dx = 2/x + 1
dy/dx = y * (2/x + 1) = x^2 * e^x * (2/x + 1)
Answer: dy/dx = x^2 * e^x * (2/x + 1)
dy/dx = x^2 * e^x * (2/x + 1)
Question: Differentiate y = (x^3 + 2x)^5 using logarithmic differentiation.
y = (x^3 + 2x)^5
ln(y) = ln((x^3 + 2x)^5)
ln(y) = 5 * ln(x^3 + 2x)
1/y * dy/dx = 5 * (3x^2 + 2) / (x^3 + 2x)
dy/dx = y * 5 * (3x^2 + 2) / (x^3 + 2x) = 5 * (x^3 + 2x)^4 * (3x^2 + 2) / (x^3 + 2x)
Answer: dy/dx = 5 * (x^3 + 2x)^4 * (3x^2 + 2) / (x^3 + 2x)
dy/dx = 5 * (x^3 + 2x)^4 * (3x^2 + 2) / (x^3 + 2x)
Question: Differentiate y = (x^2 + 1) / (x^3 + x) using logarithmic differentiation.
y = (x^2 + 1) / (x^3 + x)
ln(y) = ln((x^2 + 1) / (x^3 + x))
ln(y) = ln(x^2 + 1) - ln(x^3 + x)
1/y * dy/dx = (2x / (x^2 + 1)) - ((3x^2 + 1) / (x^3 + x))
dy/dx = y * [(2x / (x^2 + 1)) - ((3x^2 + 1) / (x^3 + x))] = (x^2 + 1) / (x^3 + x) * [(2x / (x^2 + 1)) - ((3x^2 + 1) / (x^3 + x))]
Answer: dy/dx = (x^2 + 1) / (x^3 + x) * [(2x / (x^2 + 1)) - ((3x^2 + 1) / (x^3 + x))]
dy/dx = (x^2 + 1) / (x^3 + x) * [(2x / (x^2 + 1)) - ((3x^2 + 1) / (x^3 + x))]
dy/dx = 2x * e^x
Correct Approach: Apply the chain rule to ln(x^2 * e^x).
ln(x^2 * e^x)
Misapplying Logarithm Properties: Incorrectly separating products and quotients.
ln(y) = ln(x^2) * ln(e^x)
Correct Approach: Use ln(y) = ln(x^2) + ln(e^x).
ln(y) = ln(x^2) + ln(e^x)
Ignoring Implicit Differentiation: Not differentiating both sides of the equation.
dy/dx = 2/x + 1
Correct Approach: Differentiate 1/y * dy/dx = 2/x + 1.
Incorrect Algebraic Simplification: Making errors in simplifying the final expression.
dy/dx = x^2 * e^x * (2/x)
y = x^3 * (x^2 + 1)^2
Favored Exams: AP Calculus, University Calculus
Find the Rate of Change: Asks for the derivative to find the rate of change.
y = (x^2 + 3x)^4
x = 2
Favored Exams: Engineering Entrance Exams
Maximize/Minimize Functions: Requires differentiation to find critical points.
y = (x^3 + x^2) / (x^2 + 1)
Question: What is the derivative of y = x^2 * e^x using logarithmic differentiation?
Options: A. 2x * e^x B. x^2 * e^x * (2/x + 1) C. 2x * e^x * (2/x + 1) D. x^2 * e^x
2x * e^x
x^2 * e^x * (2/x + 1)
2x * e^x * (2/x + 1)
x^2 * e^x
Correct Answer: B. x^2 * e^x * (2/x + 1)
Explanation: Apply logarithmic differentiation: ln(y) = ln(x^2 * e^x) = 2ln(x) + x, differentiate both sides, and solve for dy/dx.
ln(y) = ln(x^2 * e^x) = 2ln(x) + x
Why the Distractors Are Tempting: - A: Forgets the chain rule.- C: Incorrect application of the chain rule.- D: Ignores the logarithmic differentiation steps.
Options: A. 5 * (x^3 + 2x)^4 * (3x^2 + 2) B. 5 * (x^3 + 2x)^4 * (3x^2 + 2) / (x^3 + 2x) C. 5 * (x^3 + 2x)^4 D. 5 * (x^3 + 2x)^5
5 * (x^3 + 2x)^4 * (3x^2 + 2)
5 * (x^3 + 2x)^4 * (3x^2 + 2) / (x^3 + 2x)
5 * (x^3 + 2x)^4
5 * (x^3 + 2x)^5
Correct Answer: B. 5 * (x^3 + 2x)^4 * (3x^2 + 2) / (x^3 + 2x)
Explanation: Apply logarithmic differentiation: ln(y) = 5 * ln(x^3 + 2x), differentiate both sides, and solve for dy/dx.
Why the Distractors Are Tempting: - A: Forgets the division by the original function.- C: Ignores the chain rule.- D: Incorrect application of the power rule.
Question: What is the derivative of y = (x^2 + 1) / (x^3 + x) using logarithmic differentiation?
Options: A. (x^2 + 1) / (x^3 + x) * [(2x / (x^2 + 1)) - ((3x^2 + 1) / (x^3 + x))] B. (2x / (x^2 + 1)) - ((3x^2 + 1) / (x^3 + x)) C. (x^2 + 1) / (x^3 + x) * (2x / (x^2 + 1)) D. (x^2 + 1) / (x^3 + x) * ((3x^2 + 1) / (x^3 + x))
(x^2 + 1) / (x^3 + x) * [(2x / (x^2 + 1)) - ((3x^2 + 1) / (x^3 + x))]
(2x / (x^2 + 1)) - ((3x^2 + 1) / (x^3 + x))
(x^2 + 1) / (x^3 + x) * (2x / (x^2 + 1))
(x^2 + 1) / (x^3 + x) * ((3x^2 + 1) / (x^3 + x))
Correct Answer: A. (x^2 + 1) / (x^3 + x) * [(2x / (x^2 + 1)) - ((3x^2 + 1) / (x^3 + x))]
Explanation: Apply logarithmic differentiation: ln(y) = ln(x^2 + 1) - ln(x^3 + x), differentiate both sides, and solve for dy/dx.
Why the Distractors Are Tempting: - B: Ignores the multiplication by the original function.- C: Forgets the subtraction in the logarithm properties.- D: Incorrect application of the quotient rule.
ln(ab) = ln(a) + ln(b)
ln(a/b) = ln(a) - ln(b)
ln(a^b) = b * ln(a)
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