By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Hyperbolic functions are analogs of the ordinary trigonometric functions but are defined using the hyperbola rather than the circle. The three primary hyperbolic functions are sinh(x), cosh(x), and tanh(x). This topic appears in exams to test your understanding of these functions and their derivatives, which are essential in advanced calculus and engineering applications.
Hyperbolic functions are tested in advanced calculus exams, engineering mathematics, and physics courses. They frequently appear in questions involving differential equations, complex numbers, and special functions. These questions typically carry moderate to high marks and test your ability to apply and differentiate hyperbolic functions accurately.
tanh(x) = sinh(x) / cosh(x)
Derivatives: Know the derivatives of these functions.
d/dx [tanh(x)] = sech^2(x)
Relationships: Recognize the relationships between these functions, similar to trigonometric identities.
cosh^2(x) - sinh^2(x) = 1
Inverse Functions: Be aware of the inverse hyperbolic functions and their derivatives.
d/dx [tanh^-1(x)] = 1 / (1 - x^2)
Graphs: Visualize the graphs of these functions to understand their behavior.
The primary rule is to understand the definitions and derivatives of the hyperbolic functions: - sinh(x) = (e^x - e^-x) / 2 - cosh(x) = (e^x + e^-x) / 2 - tanh(x) = sinh(x) / cosh(x)
Imagine the hyperbola y^2 - x^2 = 1. The functions sinh(x) and cosh(x) relate to the coordinates of points on this hyperbola, similar to how sine and cosine relate to the unit circle.
Intermediate
Derivatives:
Identity:
Question: Find the derivative of sinh(x).
Step-by-Step: 1. Recall the definition: sinh(x) = (e^x - e^-x) / 2.2. Differentiate using the chain rule: d/dx [sinh(x)] = d/dx [(e^x - e^-x) / 2].3. Apply the derivative: (e^x + e^-x) / 2.4. Recognize the result: cosh(x).
Answer: cosh(x)
Question: Find the derivative of tanh(x).
Step-by-Step: 1. Recall the definition: tanh(x) = sinh(x) / cosh(x).2. Use the quotient rule: d/dx [tanh(x)] = (cosh(x) * d/dx [sinh(x)] - sinh(x) * d/dx [cosh(x)]) / cosh^2(x).3. Substitute the derivatives: (cosh(x) * cosh(x) - sinh(x) * sinh(x)) / cosh^2(x).4. Simplify: (cosh^2(x) - sinh^2(x)) / cosh^2(x).5. Recognize the identity: 1 / cosh^2(x).
Answer: sech^2(x)
Question: Prove the identity cosh^2(x) - sinh^2(x) = 1.
Step-by-Step: 1. Recall the definitions: cosh(x) = (e^x + e^-x) / 2 and sinh(x) = (e^x - e^-x) / 2.2. Square both functions: cosh^2(x) = ((e^x + e^-x) / 2)^2 and sinh^2(x) = ((e^x - e^-x) / 2)^2.3. Expand the squares: cosh^2(x) = (e^2x + 2 + e^-2x) / 4 and sinh^2(x) = (e^2x - 2 + e^-2x) / 4.4. Subtract the results: cosh^2(x) - sinh^2(x) = (e^2x + 2 + e^-2x - (e^2x - 2 + e^-2x)) / 4.5. Simplify: (4) / 4 = 1.
Answer: 1
Correct Approach: d/dx [sinh(x)] = cosh(x).
Mistake: Forgetting the quotient rule for tanh(x).
Correct Approach: d/dx [tanh(x)] = sech^2(x).
Mistake: Incorrectly applying the identity cosh^2(x) - sinh^2(x) = 1.
Correct Approach: cosh^2(x) - sinh^2(x) = 1.
Mistake: Not recognizing the inverse functions.
Exams: Calculus, Engineering Mathematics
Function Evaluation: Evaluate a hyperbolic function at a specific point.
Exams: Physics, Engineering
Identity Proof: Prove a given hyperbolic identity.
Question: What is the derivative of cosh(x)? Options: A. sinh(x) B. cosh(x) C. tanh(x) D. sech(x)
Correct Answer: A. sinh(x) Explanation: The derivative of cosh(x) is sinh(x).Why the Distractors Are Tempting: B and C are other hyperbolic functions, D is an inverse function.
Question: What is the value of tanh(0)? Options: A. 0 B. 1 C. -1 D. undefined
Correct Answer: A. 0 Explanation: tanh(0) = sinh(0) / cosh(0) = 0 / 1 = 0.Why the Distractors Are Tempting: B and C are common values for trigonometric functions, D is a trap for division by zero.
Question: Which of the following is an identity for hyperbolic functions? Options: A. cosh^2(x) + sinh^2(x) = 1 B. cosh^2(x) - sinh^2(x) = 1 C. tanh^2(x) + sech^2(x) = 1 D. cosh(x) / sinh(x) = tanh(x)
Correct Answer: B. cosh^2(x) - sinh^2(x) = 1 Explanation: This is the correct identity for hyperbolic functions.Why the Distractors Are Tempting: A is a trigonometric identity, C and D are incorrect combinations of hyperbolic functions.
Question: What is the derivative of sinh^-1(x)? Options: A. 1 / √(1 + x^2) B. 1 / √(x^2 - 1) C. 1 / (1 - x^2) D. 1 / (1 + x^2)
Correct Answer: A. 1 / √(1 + x^2) Explanation: The derivative of sinh^-1(x) is 1 / √(1 + x^2).Why the Distractors Are Tempting: B and C are derivatives of other inverse hyperbolic functions, D is a common trigonometric derivative.
Question: What is the value of cosh(0)? Options: A. 0 B. 1 C. -1 D. undefined
Correct Answer: B. 1 Explanation: cosh(0) = (e^0 + e^-0) / 2 = (1 + 1) / 2 = 1.Why the Distractors Are Tempting: A and C are common values for trigonometric functions, D is a trap for division by zero.
Join 4M+ learners. Unlock unlimited quizzes, wrong-answer tracking, flashcards + reminders, study guides, and 1-on-1 challenges.