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This topic explains how intermolecular forces (IMFs)—the attractions between molecules—determine whether a substance is a solid, liquid, or gas at room temperature. It also explains physical properties like boiling point, viscosity, surface tension, and vapor pressure. On the AP exam, you’ll predict trends, compare substances, and explain real-world phenomena (e.g., why water has a high boiling point despite its small size, or why oil and water don’t mix). Historical example: In 1912, the Titanic sank partly because the steel hull became brittle in icy water—cold temperatures weakened metallic bonds, making the metal more prone to cracking.
Ion-Dipole Forces: Attractions between ions and polar molecules (e.g., Na⁺ in water). Key for solubility.
Phase Changes: Transitions between solid, liquid, and gas. Require energy to overcome IMFs.
Deposition: Gas → solid (e.g., frost forming).
Vapor Pressure: Pressure of a gas in equilibrium with its liquid. Higher IMFs = lower vapor pressure (harder for molecules to escape).
Problem: Rank the following in order of increasing boiling point: CH₄, CH₃OH, CH₃F, CH₃CH₃.
CH₃OH (methanol): Polar with H-bonding (O-H) + dipole-dipole + LDFs.
Compare IMF strength:
For similar IMFs, larger molar mass = stronger LDFs.
Rank by IMF strength (weakest → strongest): CH₄ (LDFs, smallest) < CH₃CH₃ (LDFs, larger) < CH₃F (dipole-dipole) < CH₃OH (H-bonding).
Boiling point order (lowest → highest): CH₄ < CH₃CH₃ < CH₃F < CH₃OH.
Correction: Covalent bonds are intramolecular; IMFs are intermolecular. Breaking IMFs changes phase (e.g., melting), but breaking covalent bonds changes the molecule (e.g., combustion).
Mistake: Assuming all polar molecules have H-bonding.
Correction: H-bonding only occurs when H is bonded to N, O, or F. CH₃F is polar but has no H-bonding.
Mistake: Forgetting LDFs exist in all molecules, even nonpolar ones.
Correction: LDFs are weak but add up in large molecules (e.g., I₂ has a higher boiling point than Cl₂).
Mistake: Thinking vapor pressure increases with stronger IMFs.
Correction: Stronger IMFs = lower vapor pressure (molecules escape less easily).
Mistake: Ignoring molar mass when comparing LDFs.
H-bonding is a type of dipole-dipole, but only for H-N/O/F. Don’t call CH₃Cl an H-bonding molecule!
FRQ Favorite: Predicting properties (e.g., "Explain why H₂O has a higher boiling point than H₂S").
Answer: H₂O has H-bonding; H₂S only has dipole-dipole + LDFs.
Multiple-Choice Trap: Comparing molecules with similar molar mass but different IMFs (e.g., CH₃OH vs. CH₃SH).
Key: H-bonding (CH₃OH) > dipole-dipole (CH₃SH).
Lab-Based FRQ: Interpreting heating curves or vapor pressure data.
Which of the following has the highest boiling point? (A) CH₄ (B) CH₃Cl (C) CH₃OH (D) CH₃CH₃ Answer: (C) CH₃OH. It has H-bonding, the strongest IMF among these options.
Explain why diamond (C) has a higher melting point than sodium chloride (NaCl). Answer: Diamond is a network covalent solid with strong covalent bonds in all directions, while NaCl is an ionic solid with weaker ionic bonds (which can be disrupted by heat).
A student observes that acetone (CH₃COCH₃) evaporates faster than water at room temperature. Explain this observation using IMFs. Answer: Acetone has dipole-dipole forces, while water has H-bonding. H-bonding is stronger, so water molecules escape into the gas phase less easily, leading to slower evaporation.
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