By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
The Ideal Gas Law is a fundamental equation in chemistry and physics that describes the behavior of gases under ideal conditions. It states that the product of the pressure (P) and volume (V) of a gas is directly proportional to the product of the amount of substance (n, in moles) and the temperature (T). This relationship is expressed as PV = nRT, where R is the ideal gas constant. This topic is crucial for exams because it tests your understanding of gas behavior and your ability to apply the formula correctly, especially in choosing the right units for R.
The Ideal Gas Law is tested in various science and engineering exams, including high school chemistry, college-level physical chemistry, and professional certification exams like the MCAT and FE (Fundamentals of Engineering). It appears frequently and typically carries 5-10 marks per question. This topic tests your ability to apply mathematical formulas, understand gas behavior, and handle unit conversions accurately.
The Ideal Gas Law is expressed as PV = nRT.
Remember the mnemonic PV = nRT as "Pressure Volume equals number Right Temperature."
Intermediate
Question: Calculate the volume of 2 moles of an ideal gas at 27°C and 1 atm pressure. Step-by-Step:1. Convert temperature to Kelvin: K = 27 + 273.15 = 300.15 K2. Use R = 0.0821 L·atm/mol·K3. Plug into the formula: V = nRT/P = (2 moles * 0.0821 L·atm/mol·K * 300.15 K) / 1 atm = 50 L Answer: 50 L
Question: What is the pressure in Pascals of 3 moles of an ideal gas in a 10 L container at 300 K? Step-by-Step:1. Use R = 8.314 J/mol·K2. Convert volume to cubic meters: 10 L = 0.01 m³3. Plug into the formula: P = nRT/V = (3 moles * 8.314 J/mol·K * 300 K) / 0.01 m³ = 249,420 Pa Answer: 249,420 Pa
Question: A gas occupies 5 L at 27°C and 1 atm. What volume will it occupy at 50°C and 2 atm? Step-by-Step:1. Convert temperatures to Kelvin: 300.15 K and 323.15 K2. Use PV = nRT to find initial n: n = PV/RT = (1 atm * 5 L) / (0.0821 L·atm/mol·K * 300.15 K) = 0.2 moles3. Use n to find new volume: V = nRT/P = (0.2 moles * 0.0821 L·atm/mol·K * 323.15 K) / 2 atm = 2.64 L Answer: 2.64 L
Question: What is the value of R when pressure is in atm and volume in L? Options: A. 0.0821 L·atm/mol·K B. 8.314 J/mol·K C. 1.987 cal/mol·K D. 62.36 L·mmHg/mol·K Correct Answer: A. 0.0821 L·atm/mol·K Explanation: This is the standard value of R for these units. Why the Distractors Are Tempting: B is for Pa, C is for calories, D is for mmHg.
Question: Calculate the pressure of 2 moles of an ideal gas in a 10 L container at 300 K. Options: A. 2.48 atm B. 4.96 atm C. 9.92 atm D. 19.84 atm Correct Answer: B. 4.96 atm Explanation: Use PV = nRT with R = 0.0821. Why the Distractors Are Tempting: Incorrect unit conversions or values of R.
Question: What volume will 1 mole of an ideal gas occupy at 27°C and 2 atm? Options: A. 12.47 L B. 24.94 L C. 49.88 L D. 99.76 L Correct Answer: A. 12.47 L Explanation: Convert temperature to Kelvin and use R = 0.0821. Why the Distractors Are Tempting: Incorrect temperature or R value.
Question: A gas occupies 10 L at 27°C and 1 atm. What volume will it occupy at 100°C and 1 atm? Options: A. 10 L B. 15 L C. 20 L D. 25 L Correct Answer: C. 20 L Explanation: Use PV = nRT to find the new volume. Why the Distractors Are Tempting: Incorrect temperature conversion or R value.
Question: What is the pressure in Pascals of 1 mole of an ideal gas in a 20 L container at 300 K? Options: A. 124,710 Pa B. 249,420 Pa C. 498,840 Pa D. 997,680 Pa Correct Answer: A. 124,710 Pa Explanation: Use R = 8.314 and convert volume to cubic meters. Why the Distractors Are Tempting: Incorrect unit conversions or values of R.
Join 4M+ learners. Unlock unlimited quizzes, wrong-answer tracking, flashcards + reminders, study guides, and 1-on-1 challenges.