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Sample Table - Bonus WORKER_REF_ID BONUS_DATE BONUS_AMOUNT
1 2016-02-20 00:00:00 5000 2 2016-06-11 00:00:00 3000 3 2016-02-20 00:00:00 4000
1 2016-02-20 00:00:00 4500
2 2016-06-11 00:00:00 3500
Sample Table - Title WORKER_REF_ID WORKER_TITLE AFFECTED_FROM
1 Manager 2016-02-20 00:00:00 2 Executive 2016-06-11 00:00:00 8 Executive 2016-06-11 00:00:00 5 Manager 2016-06-11 00:00:00 4 Asst. Manager 2016-06-11 00:00:00 7 Executive 2016-06-11 00:00:00 6 Lead 2016-06-11 00:00:00 3 Lead 2016-06-11 00:00:00
SQL Script to Seed Sample Data.
CREATE DATABASE ORG; SHOW DATABASES; USE ORG;
CREATE TABLE Worker ( WORKER_ID INT NOT NULL PRIMARY KEY AUTO_INCREMENT, FIRST_NAME CHAR(25), LAST_NAME CHAR(25), SALARY INT(15), JOINING_DATE DATETIME, DEPARTMENT CHAR(25) );
INSERT INTO Worker (WORKER_ID, FIRST_NAME, LAST_NAME, SALARY, JOINING_DATE, DEPARTMENT) VALUES (001, 'Mary', 'Magdalene', 100000, '14-02-20 09.00.00', 'HR'), (002, 'Noni', 'Windsor', 80000, '14-06-11 09.00.00', 'Admin'), (003, 'Mel', 'Gibson', 300000, '14-02-20 09.00.00', 'HR'), (004, 'Ari', 'David', 500000, '14-02-20 09.00.00', 'Admin'), (005, 'Victor', 'Manuel', 500000, '14-06-11 09.00.00', 'Admin'), (006, 'Vito', 'Corleone', 200000, '14-06-11 09.00.00', 'Account'), (007, 'Jen', 'Psaki', 75000, '14-01-20 09.00.00', 'Account'), (008, 'Jennifer', 'Connolly', 90000, '14-04-11 09.00.00', 'Admin');
CREATE TABLE Bonus ( WORKER_REF_ID INT, BONUS_AMOUNT INT(10), BONUS_DATE DATETIME, FOREIGN KEY (WORKER_REF_ID) REFERENCES Worker(WORKER_ID) ON DELETE CASCADE );
INSERT INTO Bonus (WORKER_REF_ID, BONUS_AMOUNT, BONUS_DATE) VALUES (001, 5000, '16-02-20'), (002, 3000, '16-06-11'), (003, 4000, '16-02-20'), (001, 4500, '16-02-20'), (002, 3500, '16-06-11'); CREATE TABLE Title ( WORKER_REF_ID INT, WORKER_TITLE CHAR(25), AFFECTED_FROM DATETIME, FOREIGN KEY (WORKER_REF_ID) REFERENCES Worker(WORKER_ID) ON DELETE CASCADE );
INSERT INTO Title (WORKER_REF_ID, WORKER_TITLE, AFFECTED_FROM) VALUES (001, 'Manager', '2016-02-20 00:00:00'), (002, 'Executive', '2016-06-11 00:00:00'), (008, 'Executive', '2016-06-11 00:00:00'), (005, 'Manager', '2016-06-11 00:00:00'), (004, 'Asst. Manager', '2016-06-11 00:00:00'), (007, 'Executive', '2016-06-11 00:00:00'), (006, 'Lead', '2016-06-11 00:00:00'), (003, 'Lead', '2016-06-11 00:00:00');
Q 1. Write an SQL query to fetch 'FIRST_NAME' from Worker table using the alias name as <WORKER_NAME>.
Select FIRST_NAME AS WORKER_NAME from Worker;
Q 2. Write an SQL query to fetch 'FIRST_NAME' from Worker table in upper case.
Select upper(FIRST_NAME) from Worker;
Q 3. Write an SQL query to fetch unique values of DEPARTMENT from Worker table.
Select distinct DEPARTMENT from Worker;
Q 4. Write an SQL query to print the first three characters of FIRST_NAME from Worker table.
Select substring(FIRST_NAME,1,3) from Worker;
Q 5. Write an SQL query to find the position of the alphabet ('a') in the first name column 'Ari' from Worker table.
Select INSTR(FIRST_NAME, BINARY'a') from Worker where FIRST_NAME = 'Ari'; Notes.
The INSTR method is in case-sensitive by default. Using Binary operator will make INSTR work as the case-sensitive function.
Q 6. Write an SQL query to print the FIRST_NAME from Worker table after removing white spaces from the right side.
Select RTRIM(FIRST_NAME) from Worker;
Q 7. Write an SQL query to print the DEPARTMENT from Worker table after removing white spaces from the left side.
Select LTRIM(DEPARTMENT) from Worker;
Q 8. Write an SQL query that fetches the unique values of DEPARTMENT from Worker table and prints its length.
Select distinct length(DEPARTMENT) from Worker;
Q 9. Write an SQL query to print the FIRST_NAME from Worker table after replacing 'a' with 'A'.
Select REPLACE(FIRST_NAME,'a','A') from Worker;
Q 10. Write an SQL query to print the FIRST_NAME and LAST_NAME from Worker table into a single column COMPLETE_NAME. A space char should separate them.
Select CONCAT(FIRST_NAME, ' ', LAST_NAME) AS 'COMPLETE_NAME' from Worker;
Q 11. Write an SQL query to print all Worker details from the Worker table order by FIRST_NAME Ascending.
Select * from Worker order by FIRST_NAME asc;
Q 12. Write an SQL query to print all Worker details from the Worker table order by FIRST_NAME Ascending and DEPARTMENT Descending.
Select * from Worker order by FIRST_NAME asc,DEPARTMENT desc;
Q 13. Write an SQL query to print details for Workers with the first name as 'Vito' and 'Jen' from Worker table.
Select * from Worker where FIRST_NAME in ('Vito','Jen');
Q 14. Write an SQL query to print details of workers excluding first names, 'Vito' and 'Jen' from Worker table.
Select * from Worker where FIRST_NAME not in ('Vito','Jen');
Q 15. Write an SQL query to print details of Workers with DEPARTMENT name as 'Admin'.
Select * from Worker where DEPARTMENT like 'Admin%';
Q 16. Write an SQL query to print details of the Workers whose FIRST_NAME contains 'a'.
Select * from Worker where FIRST_NAME like '%a%';
Q 17. Write an SQL query to print details of the Workers whose FIRST_NAME ends with 'a'.
Select * from Worker where FIRST_NAME like '%a';
Q 18. Write an SQL query to print details of the Workers whose FIRST_NAME ends with 'h' and contains six alphabets.
Select * from Worker where FIRST_NAME like '_____h';
Q 19. Write an SQL query to print details of the Workers whose SALARY lies between 100000 and 500000.
Select * from Worker where SALARY between 100000 and 500000;
Q 20. Write an SQL query to print details of the Workers who have joined in Feb'2014.
Select * from Worker where year(JOINING_DATE) = 2014 and month(JOINING_DATE) = 2;
Q 21. Write an SQL query to fetch the count of employees working in the department 'Admin'.
SELECT COUNT(*) FROM worker WHERE DEPARTMENT = 'Admin';
Q 22. Write an SQL query to fetch worker names with salaries >= 50000 and <= 100000.
SELECT CONCAT(FIRST_NAME, ' ', LAST_NAME) As Worker_Name, Salary FROM worker WHERE WORKER_ID IN (SELECT WORKER_ID FROM worker WHERE Salary BETWEEN 50000 AND 100000);
Q 23. Write an SQL query to fetch the no. of workers for each department in the descending order.
SELECT DEPARTMENT, count(WORKER_ID) No_Of_Workers FROM worker GROUP BY DEPARTMENT ORDER BY No_Of_Workers DESC;
Q 24. Write an SQL query to print details of the Workers who are also Managers.
SELECT DISTINCT W.FIRST_NAME, T.WORKER_TITLE FROM Worker W INNER JOIN Title T ON W.WORKER_ID = T.WORKER_REF_ID AND T.WORKER_TITLE in ('Manager');
Q 25. Write an SQL query to fetch duplicate records having matching data in some fields of a table.
SELECT WORKER_TITLE, AFFECTED_FROM, COUNT(*) FROM Title GROUP BY WORKER_TITLE, AFFECTED_FROM HAVING COUNT(*) > 1;
Q 26. Write an SQL query to show only odd rows from a table.
SELECT * FROM Worker WHERE MOD (WORKER_ID, 2) <> 0;
Q 27. Write an SQL query to show only even rows from a table.
SELECT * FROM Worker WHERE MOD (WORKER_ID, 2) = 0;
Q 28. Write an SQL query to clone a new table from another table.
The general query to clone a table with data is:
SELECT * INTO WorkerClone FROM Worker; The general way to clone a table without information is:
SELECT * INTO WorkerClone FROM Worker WHERE 1 = 0; An alternate way to clone a table (for MySQL) without is:
CREATE TABLE WorkerClone LIKE Worker;
Q 29. Write an SQL query to fetch intersecting records of two tables.
(SELECT * FROM Worker) INTERSECT (SELECT * FROM WorkerClone);
Q 30. Write an SQL query to show records from one table that another table does not have.
SELECT * FROM Worker MINUS SELECT * FROM Title;
Q 31. Write an SQL query to show the current date and time.
Following MySQL query returns the current date:
SELECT CURDATE(); Following MySQL query returns the current date and time:
SELECT NOW(); Following SQL Server query returns the current date and time:
SELECT getdate(); Following Oracle query returns the current date and time:
SELECT SYSDATE FROM DUAL;
Q 32. Write an SQL query to show the top n (say 10) records of a table.
Following MySQL query will return the top n records using the LIMIT method:
SELECT * FROM Worker ORDER BY Salary DESC LIMIT 10; Following SQL Server query will return the top n records using the TOP command:
SELECT TOP 10 * FROM Worker ORDER BY Salary DESC; Following Oracle query will return the top n records with the help of ROWNUM:
SELECT * FROM (SELECT * FROM Worker ORDER BY Salary DESC) WHERE ROWNUM <= 10;
Q 33. Write an SQL query to determine the nth (say n=5) highest salary from a table.
The following MySQL query returns the nth highest salary:
SELECT Salary FROM Worker ORDER BY Salary DESC LIMIT n-1,1; The following SQL Server query returns the nth highest salary:
SELECT TOP 1 Salary FROM ( SELECT DISTINCT TOP n Salary FROM Worker ORDER BY Salary DESC ) ORDER BY Salary ASC;
Q 34. Write an SQL query to determine the 5th highest salary without using TOP or limit method.
The following query is using the correlated subquery to return the 5th highest salary:
SELECT Salary FROM Worker W1 WHERE 4 = ( SELECT COUNT( DISTINCT ( W2.Salary ) ) FROM Worker W2 WHERE W2.Salary >= W1.Salary ); Use the following generic method to find nth highest salary without using TOP or limit.
SELECT Salary FROM Worker W1 WHERE n-1 = ( SELECT COUNT( DISTINCT ( W2.Salary ) ) FROM Worker W2 WHERE W2.Salary >= W1.Salary );
Q 35. Write an SQL query to fetch the list of employees with the same salary.
Select distinct W.WORKER_ID, W.FIRST_NAME, W.Salary from Worker W, Worker W1 where W.Salary = W1.Salary and W.WORKER_ID != W1.WORKER_ID;
Q 36. Write an SQL query to show the second highest salary from a table.
Select max(Salary) from Worker where Salary not in (Select max(Salary) from Worker);
Q 37. Write an SQL query to show one row twice in results from a table.
select FIRST_NAME, DEPARTMENT from worker W where W.DEPARTMENT='HR' union all select FIRST_NAME, DEPARTMENT from Worker W1 where W1.DEPARTMENT='HR';
Q 38. Write an SQL query to fetch intersecting records of two tables.
Q 39. Write an SQL query to fetch the first 50% records from a table.
SELECT * FROM WORKER WHERE WORKER_ID <= (SELECT count(WORKER_ID)/2 from Worker);
Q 40. Write an SQL query to fetch the departments that have less than five people in it.
SELECT DEPARTMENT, COUNT(WORKER_ID) as 'Number of Workers' FROM Worker GROUP BY DEPARTMENT HAVING COUNT(WORKER_ID) < 5;
Q 41. Write an SQL query to show all departments along with the number of people in there.
The following query returns the expected result:
SELECT DEPARTMENT, COUNT(DEPARTMENT) as 'Number of Workers' FROM Worker GROUP BY DEPARTMENT;
Q 42. Write an SQL query to show the last record from a table.
The following query will return the last record from the Worker table:
Select * from Worker where WORKER_ID = (SELECT max(WORKER_ID) from Worker);
Q 43. Write an SQL query to fetch the first row of a table.
Select * from Worker where WORKER_ID = (SELECT min(WORKER_ID) from Worker);
Q 44. Write an SQL query to fetch the last five records from a table.
SELECT * FROM Worker WHERE WORKER_ID <=5 UNION SELECT * FROM (SELECT * FROM Worker W order by W.WORKER_ID DESC) AS W1 WHERE W1.WORKER_ID <=5;
Q 45. Write an SQL query to print the name of employees having the highest salary in each department.
SELECT t.DEPARTMENT,t.FIRST_NAME,t.Salary from(SELECT max(Salary) as TotalSalary,DEPARTMENT from Worker group by DEPARTMENT) as TempNew Inner Join Worker t on TempNew.DEPARTMENT=t.DEPARTMENT and TempNew.TotalSalary=t.Salary;
Q 46. Write an SQL query to fetch three max salaries from a table.
SELECT distinct Salary from worker a WHERE 3 >= (SELECT count(distinct Salary) from worker b WHERE a.Salary <= b.Salary) order by a.Salary desc;
Q 47. Write an SQL query to fetch three min salaries from a table.
SELECT distinct Salary from worker a WHERE 3 >= (SELECT count(distinct Salary) from worker b WHERE a.Salary >= b.Salary) order by a.Salary desc;
Q 48. Write an SQL query to fetch nth max salaries from a table.
SELECT distinct Salary from worker a WHERE n >= (SELECT count(distinct Salary) from worker b WHERE a.Salary <= b.Salary) order by a.Salary desc;
Q 49. Write an SQL query to fetch departments along with the total salaries paid for each of them.
SELECT DEPARTMENT, sum(Salary) from worker group by DEPARTMENT;
Q 50. Write an SQL query to fetch the names of workers who earn the highest salary.
SELECT FIRST_NAME, SALARY from Worker WHERE SALARY=(SELECT max(SALARY) from Worker);
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