By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Circles — Equation of Circle, Tangent and Normal, Chord of Contact is a fundamental topic in JEE, appearing in 2-3 questions every year. It's moderately difficult, with some questions demanding attention to detail. This topic is crucial for both JEE Main and Advanced, so it's essential to master it.
Exam board insight: The examiners may penalize incorrect assumptions.
The mistake: Not converting the equation to standard form.
Exam board insight: The examiners may penalize incorrect conversion.
The mistake: Not applying the condition of perpendicularity or parallelism.
Exam board insight: The examiners may penalize incorrect application.
The mistake: Not using the correct formula for the equation of the tangent or normal.
The mistake: Not checking the domain or range of the equation.
Question 1: Find the equation of the tangent to the circle x² + y² = 4 at the point (1, ?3).
A) y = x + ?3 B) y = -x + ?3 C) y = x - ?3 D) y = -x - ?3
Answer: A) y = x + ?3 Solution: The equation of the tangent is y = mx + c, where m is the slope and c is the y-intercept. The slope of the radius is -?3/1 = -?3, so the slope of the tangent is 1/?3. The equation of the tangent is y = (1/?3)x + ?3.
Common Wrong Answer: Option B) y = -x + ?3 is tempting because it has the correct slope, but the y-intercept is incorrect.
Question 2: Find the equation of the normal to the circle x² + y² = 4 at the point (1, -?3).
A) y = x - ?3 B) y = -x + ?3 C) y = x + ?3 D) y = -x - ?3
Answer: B) y = -x + ?3 Solution: The equation of the normal is y = mx + c, where m is the slope and c is the y-intercept. The slope of the radius is ?3/1 = ?3, so the slope of the normal is -1/?3. The equation of the normal is y = (-1/?3)x + ?3.
Common Wrong Answer: Option A) y = x - ?3 is tempting because it has the correct slope, but the y-intercept is incorrect.
Question 3: Find the length of the chord of contact of the circle x² + y² = 4 with respect to the point (2, 0).
A) 2?5 B) ?5 C) 2?2 D) ?2
Answer: A) 2?5 Solution: The equation of the chord of contact is xx1 + yy1 = x1² + y1², where (x1, y1) is the point (2, 0). Substituting the values, we get x(2) + y(0) = 2² + 0², which simplifies to 2x = 4. The length of the chord is 2?5.
Common Wrong Answer: Option B) ?5 is tempting because it's a factor of 2?5, but it's not the correct answer.
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