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Applied Chemistry 2: Concept of Electrochemistry
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Applied Chemistry 2: Concept of Electrochemistry
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19 Questions

1. The weight of silver displaced by a quantity of electricity which displaces 5600ml of O2 at STP will be
2. The equivalent conductance of Ba2+ and Cl– are respectively 127 and 76 ohm-1 cm-1 eq-1 at infinite dilution. The equivalent conductance of BaCl2 at infinite dilution will be
3. When heating one end of a metal plate, the other end gets hot because of
4. A device that converts the energy of combustion of fields like hydrogen and methane directly into electrical energy is known as
5. The reaction, 3ClO– (aq) → ClO3 (aq) + 2Cl– (aq) is an example of
6. NH4NC>3 is used in salt bridge because
7. If limiting molar conductivity of Ca2+ and Cl– are 119.0 and 76.3 S cm2 mol-1, then the value of limiting molar conductivity of CaCl2 will be
8. Which reaction is not feasible?
9. Which of the following reaction is used to make fuel cell?
3
10. Which of the following reaction is used to make fuel cell?
3
11. If E°Fe2+/Fe = -0.441 V and E°Fe2+/Fe2+ = 0.771 V, the standard EMF of the reaction, Fe + 2Fe3+ → 3Fe2+ will be
12. The emf of the cell: Ni / Ni2+ (1.0 M) // Au3+ (1.0 M) / Au (E° = -0.25 V for Ni2+/Ni; E° = 1.5 V for Au3+/Au) is
13. The aqueous solution of which of the following compounds is the best conductor of electric current?
14. Once a current of 1.0 ampere was passed through one litre of CuCl2 solution for 16 min and 5 sec, all of the solution’s copper was deposited at the cathode. The strength of solution CuCl2 was (Molar mass of Cu = 63.5; Faraday constant = 96,500 C/mol)
15. The cell reaction of the galvanic cell.
2
16. NH4NC>3 is used in salt bridge because
17. A device that converts the energy of combustion of fields like hydrogen and methane directly into electrical energy is known as
18. The standard emf of a galvanic cell involving cell reaction with n = 2 is formed to be 0.295 V at 25° C. The equilibrium constant of the reaction would be - [Given F = 96500 (mol-1); R = 8.314 JK-1 mol-1]
19. The emf of the cell: Ni / Ni2+ (1.0 M) // Au3+ (1.0 M) / Au (E° = -0.25 V for Ni2+/Ni; E° = 1.5 V for Au3+/Au) is

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