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By the end of this topic, students will be able to:
A straight line graph is a graphical representation of a linear relationship between two variables, x and y. The equation of a straight line is given by the formula y = mx + c, where m is the gradient (or slope) of the line and c is the y-intercept (the point where the line crosses the y-axis).
The gradient (m) of a straight line represents the rate of change of y with respect to x. It can be positive, negative, or zero, and it determines the steepness of the line. A positive gradient indicates that the line slopes upwards from left to right, while a negative gradient indicates that the line slopes downwards from left to right.
The y-intercept (c) of a straight line is the point where the line crosses the y-axis. It represents the value of y when x is equal to zero.
The equation of a straight line is y = 2x + 3. Plot the graph and identify the x-intercept and y-intercept.
To plot the graph, we need to find two points on the line. We can do this by substituting different values of x into the equation and finding the corresponding values of y.
For example, if we substitute x = 0 into the equation, we get y = 2(0) + 3 = 3. This means that the point (0, 3) is on the line.
If we substitute x = 1 into the equation, we get y = 2(1) + 3 = 5. This means that the point (1, 5) is also on the line.
We can plot these two points on a coordinate grid and draw a straight line through them to represent the graph of the equation.
The x-intercept of the line is the point where the line crosses the x-axis. To find this point, we need to set y = 0 and solve for x.
0 = 2x + 3 2x = -3 x = -3/2
So, the x-intercept of the line is the point (-3/2, 0).
The y-intercept of the line is the point where the line crosses the y-axis. We already found this point to be (0, 3).
A car travels at a constant speed of 60 miles per hour. If it starts at a point 20 miles from the city center, how long will it take to reach the city center?
Let x be the time in hours and y be the distance in miles. The equation of the straight line representing the car's journey is y = 60x + 20.
We want to find the time it takes for the car to reach the city center, which is 0 miles from the city center. So, we set y = 0 and solve for x.
0 = 60x + 20 60x = -20 x = -20/60 x = -1/3
So, it will take the car 1/3 hour to reach the city center.
What is the gradient of the straight line with equation y = 2x + 3?
A) 1 B) 2 C) -2 D) 0
Correct answer: B) 2 Why the distractors fail: A) 1 is the gradient of the line y = x + 3, not y = 2x + 3. C) -2 is the negative of the gradient of the line y = 2x + 3. D) 0 is the gradient of the line y = 3, not y = 2x + 3.
What is the equation of the straight line with gradient 2 and y-intercept 3?
A) y = 2x + 3 B) y = 2x - 3 C) y = -2x + 3 D) y = -2x - 3
Correct answer: A) y = 2x + 3 Why the distractors fail: B) y = 2x - 3 has a negative y-intercept. C) y = -2x + 3 has a negative gradient. D) y = -2x - 3 has a negative gradient and a negative y-intercept.
What is the x-intercept of the straight line with equation y = 2x + 3?
A) (-3/2, 0) B) (3/2, 0) C) (-1/2, 0) D) (1/2, 0)
Correct answer: A) (-3/2, 0) Why the distractors fail: B) (3/2, 0) is the x-intercept of the line y = -2x + 3, not y = 2x + 3. C) (-1/2, 0) is not the x-intercept of the line y = 2x + 3. D) (1/2, 0) is not the x-intercept of the line y = 2x + 3.
A straight line has an equation of the form y = mx + c. What is the value of c when the line passes through the point (1, 2)?
A) 1 B) 2 C) 3 D) 4
Correct answer: C) 3 Why the distractors fail: A) 1 is the value of m, not c. B) 2 is the value of y when x is 1, but it is not the value of c. D) 4 is not the value of c.
What is the y-intercept of the straight line with equation y = 2x + 3?
A) 0 B) 3 C) -3 D) 1
Correct answer: B) 3 Why the distractors fail: A) 0 is the y-intercept of the line y = 2x, not y = 2x + 3. C) -3 is the negative of the y-intercept of the line y = 2x + 3. D) 1 is not the y-intercept of the line y = 2x + 3.
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