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If (x+1/x)2=3 then the value of, x206+x200+x90+x84+x18+x12+x6+1 is,

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If (x+1/x)<sup>2</sup>=3 then the value of, x<sup>206</sup>+x200+x90+x<sup>84</sup>+x<sup>18</sup>+x<sup>12</sup>+x<sup>6</sup>+1 is,





 
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