By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
(For SSC / Bank / Railway Exams – Ace Your Math Section!)
"Master polynomial equations, and you unlock 5–10 marks in your SSC/Bank/Railway exam—questions that look scary but follow a simple 3-step method. Let’s break it down."
(On camera: Hold up a past paper with a polynomial question highlighted.) "This one question could be the difference between a pass and a fail. Today, you’ll learn how to solve it in under 2 minutes."
Before diving in, ensure you understand: 1. Factorisation – Breaking expressions like (x^2 - 5x + 6) into ((x-2)(x-3)). 2. Zero Product Property – If (A \times B = 0), then (A = 0) or (B = 0). 3. Basic Algebra – Solving linear equations like (2x + 3 = 0).
(On camera: Quick quiz – "Can you factorise (x^2 - 9)? If yes, you’re ready!)
(On camera: Point to each term and give a 2-second example.)
MEMORISE THIS (not always given in exams).
Sum & Product of Roots (for (ax^2 + bx + c = 0)) [ \text{Sum} = -\frac{b}{a}, \quad \text{Product} = \frac{c}{a} ]
"Given on exam sheet" (but memorising saves time).
Factor Theorem
(On camera: Write each formula on screen, then cover and ask: "What’s the quadratic formula?")
Goal: Solve (P(x) = 0) (find all roots).
(On camera: Demonstrate each step with a simple example, like (x^2 - 9 = 0).)
Solve: (x^2 - 5x + 6 = 0)
Step 1: No common factors. Step 2: Factorise → ((x-2)(x-3) = 0). Step 3: Zero Product Property → (x = 2) or (x = 3). Answer: (x = 2, 3).
What we did and why: - We factored the quadratic because it’s the fastest method when possible. - Always check if the quadratic can be factored before using the formula.
Solve: (x^3 - 6x^2 + 11x - 6 = 0)
Step 1: No common factors. Step 2: Use Factor Theorem → Try (x=1): (1 - 6 + 11 - 6 = 0) → ((x-1)) is a factor. Divide (x^3 - 6x^2 + 11x - 6) by ((x-1)) → (x^2 -5x +6). Step 3: Factorise (x^2 -5x +6) → ((x-2)(x-3)). So, (x^3 - 6x^2 + 11x - 6 = (x-1)(x-2)(x-3)). Step 4: Zero Product Property → (x = 1, 2, 3). Answer: (x = 1, 2, 3).
What we did and why: - We guessed (x=1) because it’s a common root for simple cubics. - Always divide the polynomial by ((x - \text{root})) to reduce the degree.
Solve: (2x^4 - 5x^2 + 3 = 0)
Step 1: Let (y = x^2) → Equation becomes (2y^2 -5y +3 = 0). Step 2: Factorise → ((2y-3)(y-1) = 0). Step 3: Solve for (y) → (y = \frac{3}{2}) or (y = 1). Step 4: Substitute back (y = x^2) → - (x^2 = \frac{3}{2}) → (x = \pm \sqrt{\frac{3}{2}}). - (x^2 = 1) → (x = \pm 1). Answer: (x = \pm 1, \pm \sqrt{\frac{3}{2}}).
What we did and why: - We used substitution to turn a quartic into a quadratic. - Always check if the equation can be simplified with substitution.
(On camera: Hold up a wrong solution and ask: "Spot the mistake!)
(On camera: Show a past paper question with a trap and say: "This is a classic! Here’s how to beat it.")
(Spoken naturally, as if to a student the night before the exam.)
"Okay, listen up—this is all you need to remember for polynomial equations:
And one last thing—always check your answers. Plug them back into the original equation to make sure they work. Examiners love to trick you with extraneous roots.
You’ve got this. Now go solve those equations like a pro!
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