By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Introduction Mastering evolution in NEET UG can secure 8-10 marks—enough to push you into the top 1%. Whether it’s calculating allele frequencies, identifying speciation types, or tracing human ancestry, this topic appears in every NEET paper and is easier to score than genetics or ecology if you follow a structured approach.
(If you’re shaky on these, pause and review them first—this guide assumes you know them.)
Formula: p² + 2pq + q² = 1 p + q = 1
MEMORISE THIS – The formula is not given in NEET, but the conditions are (see below).
For allele frequencies to remain constant (no evolution), all 5 must be true:1. No mutations – No new alleles.2. No gene flow – No migration in/out.3. Large population – No genetic drift.4. No natural selection – All traits equally fit.5. Random mating – No sexual selection.
Exam Trap: If any one condition is violated, evolution is happening.
Question: In a population, 36% of individuals are homozygous recessive (aa). What is the frequency of the dominant allele (A)?
Step 1: Identify problem type → Hardy-Weinberg. Step 2: Given → q² = 36% = 0.36 (homozygous recessive). Step 3: Find q → q = √0.36 = 0.6. Step 4: Find p → p = 1 - q = 1 - 0.6 = 0.4. Step 5: Frequency of dominant allele (A) = p = 0.4 (40%).
What we did and why: - q² was given → took square root to find q. - Used p + q = 1 to find p. - No violations → allele frequencies stay constant.
Question: A population of frogs is split by a river. After 10,000 years, the two groups cannot interbreed. What type of speciation occurred? If the original population had 16% homozygous recessive (aa), what is the frequency of heterozygotes (Aa) in the new populations?
Step 1: Identify problem type → Speciation + Hardy-Weinberg. Step 2: - Speciation: Geographic barrier (river) → allopatric speciation. - Hardy-Weinberg: Given q² = 16% = 0.16. Step 3: - Find q → q = √0.16 = 0.4. - Find p → p = 1 - 0.4 = 0.6. - Find 2pq → 2 × 0.6 × 0.4 = 0.48 (48%). Step 4: Check violations → Gene flow stopped (river barrier) → evolution occurred. Step 5: - Speciation type: Allopatric (geographic barrier). - Heterozygote frequency: 48%.
What we did and why: - River = geographic barrier → allopatric speciation. - q² given → found q, p, then 2pq. - Violation (gene flow stopped) → evolution happened.
Question: Which of the following is NOT an example of adaptive radiation? A) Darwin’s finches evolving different beak shapes B) Marsupials in Australia evolving into diverse species C) Peppered moths changing color due to industrial pollution D) Cichlid fish in Lake Victoria evolving into many species
Step 1: Identify problem type → Adaptive radiation (definition test). Step 2: Recall definition → One ancestor → many species in different niches. Step 3: - A) Finches → one ancestor → many beak shapes → adaptive radiation. - B) Marsupials → one ancestor → many species → adaptive radiation. - C) Peppered moths → one species changing color (natural selection, not radiation). - D) Cichlid fish → one ancestor → many species → adaptive radiation. Step 4: C is NOT adaptive radiation (it’s directional selection). Step 5: Answer = C.
What we did and why: - Adaptive radiation = one ancestor → many species. - Peppered moths = one species changing (not radiation). - Exam trap: Confusing natural selection with adaptive radiation.
"Listen up—this is your 8-mark evolution cheat sheet for NEET.
All 5 conditions must be met for no evolution—if any is broken, evolution is happening.
Speciation:
Partial barrier + hybrid zone? → Parapatric.
Adaptive radiation:
Not the same as natural selection (e.g., peppered moths = not radiation).
Human evolution:
Now go crush those 8 marks—you’ve got this!
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