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Mastering Surface Chemistry unlocks 5-7 direct NEET questions (18-25 marks) on adsorption, colloids, and their real-world applications—like water purification, drug delivery, and even how vaccines work. If you want a top 100 rank, this is a must-ace topic.
Before diving in, ensure you understand:1. Colloidal systems – Difference between true solutions, colloids, and suspensions.2. Intermolecular forces – Van der Waals forces, hydrogen bonding, and electrostatic attraction.3. Basic thermodynamics – Concepts of enthalpy (ΔH) and entropy (ΔS).
Problem: At 25°C, the adsorption of a gas on charcoal follows Freundlich isotherm. Given: - At P = 1 atm, x/m = 0.2 g/g. - At P = 4 atm, x/m = 0.4 g/g. Find k and n.
Solution:1. Write Freundlich equation: [ \frac{x}{m} = kP^{1/n} ]2. Take log on both sides: [ \log \left( \frac{x}{m} \right) = \log k + \frac{1}{n} \log P ]3. Plug in values: - For P = 1 atm, x/m = 0.2: [ \log 0.2 = \log k + \frac{1}{n} \log 1 \implies \log k = \log 0.2 ] - For P = 4 atm, x/m = 0.4: [ \log 0.4 = \log 0.2 + \frac{1}{n} \log 4 ]4. Solve for n: [ \log 0.4 - \log 0.2 = \frac{1}{n} \log 4 ] [ \log \left( \frac{0.4}{0.2} \right) = \frac{1}{n} \log 4 \implies \log 2 = \frac{1}{n} \log 4 ] [ \log 2 = \frac{1}{n} \cdot 2 \log 2 \implies n = 2 ]5. Find k: [ \log k = \log 0.2 \implies k = 0.2 ] Answer: k = 0.2, n = 2
What we did and why: - Used logarithmic form to linearize the equation. - Compared two points to find slope (1/n) and intercept (log k).
Problem: Which of the following electrolytes will coagulate a negatively charged As₂S₃ sol most effectively? (A) NaCl (B) BaCl₂ (C) AlCl₃ (D) K₂SO₄
Solution:1. Hardy-Schulze rule: Higher valency of counter ion → stronger coagulation.2. As₂S₃ sol is negatively charged → cation valency matters.3. Compare cations: - Na⁺ (valency = +1) - Ba²⁺ (valency = +2) - Al³⁺ (valency = +3) - K⁺ (valency = +1)4. Al³⁺ has the highest valency → most effective coagulant.
Answer: (C) AlCl₃
What we did and why: - Applied Hardy-Schulze rule (higher valency → better coagulation). - Identified the charge of the sol (negative → cation effect).
Problem: A colloidal solution of Fe(OH)₃ is subjected to an electric field. What will be observed?1. Particles move to the anode.2. Particles move to the cathode.3. No movement.4. Solution becomes colorless.
Solution:1. Fe(OH)₃ sol is positively charged (due to adsorption of Fe³⁺ ions).2. Electrophoresis: Positively charged particles move to the cathode (negative electrode).3. Tyndall effect: Colloidal solutions scatter light (not colorless).
Answer: (2) Particles move to the cathode.
What we did and why: - Recognized Fe(OH)₃ is positively charged. - Applied electrophoresis rules (opposite charges attract).
"Listen up—this is your 60-second crash course for Surface Chemistry in NEET:
Last tip: If a question mentions light scattering, it’s Tyndall effect. If it’s about electric field movement, it’s electrophoresis. If it’s about precipitation, it’s coagulation.
You’ve got this—go ace it!
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