3 friends a, b and c went for an internship in a company. They had different levels of experiences. If their age was in a ratio 4 : 5 : 6 and their experience was in a ratio 2 : 3 : 4 respectively, find the friend with the least age to start working. It is known that the ratio of their total age to their total experience is 10 : 1.

If the current age is x, then age n years later = x+n. If the current age is x, then age n years ago = x – n. The ages in a ratio a : b will be ax and bx. If the current age is x, then 1 /n of the age is x/n. If you assume the current age to be x, then the age after n years will be (x+n) years. If you assume the current age to be x, then the age before n years will be (x-n) years. If the age is given in the form of a ratio, for example, p:q, then the age shall be considered as qx and px If you assume the current age to be x, then n times the current age will be (x×n) years If you assume... Show more

If the current age is x, then age n years later = x+n. If the current age is x, then age n years ago = x – n. The ages in a ratio a : b will be ax and bx. If the current age is x, then 1 /n of the age is x/n.

If you assume the current age to be x, then the age after n years will be (x+n) years.
If you assume the current age to be x, then the age before n years will be (x-n) years.
If the age is given in the form of a ratio, for example, p:q, then the age shall be considered as qx and px
If you assume the current age to be x, then n times the current age will be (x×n) years
If you assume the current age to be x, then 1/n of the age shall be equal to (x/n) years

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