My age in my sister’s wedding was half my age now. My sister’s age in her wedding was equal to my age now. If my sister got wedded 18 years back, find the ratio of my sister’s age to my age 12 years later.

If the current age is x, then age n years later = x+n. If the current age is x, then age n years ago = x – n. The ages in a ratio a : b will be ax and bx. If the current age is x, then 1 /n of the age is x/n. If you assume the current age to be x, then the age after n years will be (x+n) years. If you assume the current age to be x, then the age before n years will be (x-n) years. If the age is given in the form of a ratio, for example, p:q, then the age shall be considered as qx and px If you assume the current age to be x, then n times the current age will be (x×n) years If you assume... Show more

If the current age is x, then age n years later = x+n. If the current age is x, then age n years ago = x – n. The ages in a ratio a : b will be ax and bx. If the current age is x, then 1 /n of the age is x/n.

If you assume the current age to be x, then the age after n years will be (x+n) years.
If you assume the current age to be x, then the age before n years will be (x-n) years.
If the age is given in the form of a ratio, for example, p:q, then the age shall be considered as qx and px
If you assume the current age to be x, then n times the current age will be (x×n) years
If you assume the current age to be x, then 1/n of the age shall be equal to (x/n) years

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