The total age of a group of 9 students is 171 years. The average age of another group half of the average age of first group. If there are 6 people in group, find the average age of both the groups put together.

If the current age is x, then age n years later = x+n. If the current age is x, then age n years ago = x – n. The ages in a ratio a : b will be ax and bx. If the current age is x, then 1 /n of the age is x/n. If you assume the current age to be x, then the age after n years will be (x+n) years. If you assume the current age to be x, then the age before n years will be (x-n) years. If the age is given in the form of a ratio, for example, p:q, then the age shall be considered as qx and px If you assume the current age to be x, then n times the current age will be (x×n) years If you assume... Show more

If the current age is x, then age n years later = x+n. If the current age is x, then age n years ago = x – n. The ages in a ratio a : b will be ax and bx. If the current age is x, then 1 /n of the age is x/n.

If you assume the current age to be x, then the age after n years will be (x+n) years.
If you assume the current age to be x, then the age before n years will be (x-n) years.
If the age is given in the form of a ratio, for example, p:q, then the age shall be considered as qx and px
If you assume the current age to be x, then n times the current age will be (x×n) years
If you assume the current age to be x, then 1/n of the age shall be equal to (x/n) years

Show less