There are 5 members in a family. If their ages are in a series with equal gaps, find the age of the eldest person. It is known that the sum of their ages is 120 years, and no one is younger than 20 years and older than 30 years.

If the current age is x, then age n years later = x+n. If the current age is x, then age n years ago = x – n. The ages in a ratio a : b will be ax and bx. If the current age is x, then 1 /n of the age is x/n. If you assume the current age to be x, then the age after n years will be (x+n) years. If you assume the current age to be x, then the age before n years will be (x-n) years. If the age is given in the form of a ratio, for example, p:q, then the age shall be considered as qx and px If you assume the current age to be x, then n times the current age will be (x×n) years If you assume... Show more

If the current age is x, then age n years later = x+n. If the current age is x, then age n years ago = x – n. The ages in a ratio a : b will be ax and bx. If the current age is x, then 1 /n of the age is x/n.

If you assume the current age to be x, then the age after n years will be (x+n) years.
If you assume the current age to be x, then the age before n years will be (x-n) years.
If the age is given in the form of a ratio, for example, p:q, then the age shall be considered as qx and px
If you assume the current age to be x, then n times the current age will be (x×n) years
If you assume the current age to be x, then 1/n of the age shall be equal to (x/n) years

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