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Find the sum of 9+\(\frac{1}{√9}+\frac{1}{9+√9}-\frac{1}{9-√9}\).

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The number 2 is multiplied once again by 2 to produce the number 4, so 2 is considered a square root of 4. The cube root follows the same lines, except that a number must be multiplied by itself three times.


Find the sum of 9+\(\frac{1}{√9}+\frac{1}{9+√9}-\frac{1}{9-√9}\).






 
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