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If \(\sqrt{1+\frac{x}{225}}=\frac{17}{15}\), then find the value of x.

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The number 2 is multiplied once again by 2 to produce the number 4, so 2 is considered a square root of 4. The cube root follows the same lines, except that a number must be multiplied by itself three times.


If \(\sqrt{1+\frac{x}{225}}=\frac{17}{15}\), then find the value of x.






 
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