By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Lines, Circles, Distance Formula, Midpoint
Coordinate geometry appears on every ACT Math test (typically 4–6 questions). You’ll work with points, lines, slopes, distances, midpoints, and circles on the xy-plane. Real-world example: A city planner uses coordinate geometry to determine the shortest route between two subway stations (distance formula) or the center of a circular park (circle equation). A typical ACT question might ask: "What is the equation of the line passing through (2, 3) and perpendicular to y = –4x + 1?"
Mistake: Mixing up the order of points in the distance/midpoint formulas. Correction: Always subtract x₂ – x₁ and y₂ – y₁ (not x₁ – x₂). For midpoint, add first, then divide.
Mistake: Forgetting to take the negative reciprocal for perpendicular slopes. Correction: If the original slope is m, the perpendicular slope is –1/m. Example: m = 2 → perpendicular slope = –1/2.
Mistake: Misidentifying the center of a circle from its equation. Correction: The center is (h, k), not (–h, –k). Example: (x – 3)² + (y + 2)² = 25 → center = (3, –2).
Mistake: Assuming all lines with the same y-intercept are parallel. Correction: Parallel lines must have the same slope, not just the same y-intercept.
Mistake: Forgetting to square the radius in the circle equation. Correction: If the radius is r, the equation uses r². Example: Radius = 5 → equation uses 25.
√((4–1)² + (6–2)²)
What is the slope of the line perpendicular to y = –3/4x + 5? A) 3/4 B) –4/3 C) 4/3 D) –3/4 Answer: C) 4/3. Perpendicular slopes are negative reciprocals (–3/4 → 4/3).
Find the distance between (–1, 5) and (3, –2). A) 5 B) √65 C) √53 D) 7 Answer: B) √65. Distance = √[(3 – (–1))² + (–2 – 5)²] = √(16 + 49) = √65.
What is the center of the circle with equation (x + 2)² + (y – 7)² = 16? A) (2, –7) B) (–2, 7) C) (2, 7) D) (–2, –7) Answer: B) (–2, 7). The equation is (x – (–2))² + (y – 7)² = 16, so center = (–2, 7).
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