By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Q: What is a geometric series? A: A series where each term is obtained by multiplying the previous term by a constant ratio r. Trap/Clarification: The series starts at n=0 (or n=1) but the convergence condition |r| < 1 is independent of the starting index.
Q: What is the harmonic series? A: The series ?(1/n) from n=1 to ?, which diverges. Trap/Clarification: The terms 1/n-0, but this is not sufficient for convergence (divergence is proven via integral test or comparison).
Q: Why does the geometric series converge only if |r| < 1? A: For |r|-1, the terms do not approach zero, violating the nth-term test for divergence. Trap/Clarification: The sum formula a/(1?r) is only valid for |r| < 1; otherwise, the series diverges.
Q: Why is the harmonic series important? A: It demonstrates that a series can diverge even if its terms approach zero, disproving a common misconception. Trap/Clarification: The harmonic series grows very slowly (like ln(n)), but it still diverges to ?.
Q: How do you find the sum of a convergent geometric series? A: Use the formula S = a/(1?r), where a is the first term and |r| < 1. Trap/Clarification: If the series starts at n=k-0, adjust a to the first term (e.g., ar? for n=k).
Q: How is a telescoping series evaluated? A: Write out the partial sums, observe cancellation, and take the limit of the remaining terms as n-?. Trap/Clarification: Not all series with cancellation are telescoping (e.g., ?(1/(n(n+1))) is; ?(1/n²) is not).
Q: Can a geometric series converge if r = 1? A: No; the series becomes ?a (a constant), which diverges unless a = 0. Trap/Clarification: r = ?1 also diverges (oscillates between a and ?a).
Q: Under what conditions does a telescoping series converge? A: The limit of the remaining boundary terms must exist as n-?. Trap/Clarification: Even if terms cancel, the series may diverge if the limit of the partial sums does not exist (e.g., ?(1/n-1/(n+1)) converges to 1; ?(1) diverges).
Statement: If the terms of a series approach zero, the series converges. Answer: FALSE Why the common mistake happens: Overgeneralizing the nth-term test (which only proves divergence, not convergence).
Statement: The series ?(2?/3?) is geometric and converges. Answer: TRUE Why the common mistake happens: Misidentifying r as 2/3 (correct) but forgetting to check |r| < 1 (which holds here).
Statement: All telescoping series converge. Answer: FALSE Why the common mistake happens: Assuming cancellation guarantees convergence (e.g., ?(1) is telescoping but diverges).
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