By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Q: What is the velocity vector? A: The instantaneous rate of change of the position vector, v(t) = r'(t), representing both speed and direction. Trap/Clarification: Velocity is not the same as speed—speed is the magnitude of velocity (a scalar), while velocity is a vector.
Q: What is the difference between speed and velocity? A: Speed is the magnitude of velocity (?v(t)?), a scalar; velocity is a vector with both magnitude and direction. Trap/Clarification: Speed can never be negative, but velocity components (e.g., x'(t)) can be negative if motion reverses direction.
Q: Why is the acceleration vector not always parallel to the velocity vector? A: Because acceleration has two components: tangential (parallel to velocity, changes speed) and normal (perpendicular to velocity, changes direction). Trap/Clarification: If acceleration is only tangential (e.g., straight-line motion), it is parallel to velocity; otherwise, it’s not.
Q: Why is speed the magnitude of velocity, not the derivative of position’s magnitude? A: The derivative of ?r(t)? gives the rate of change of distance from the origin, not the path length traveled (speed). Speed requires ?v(t)?. Trap/Clarification: d/dt ?r(t)?-?v(t)? unless motion is purely radial (e.g., straight line from origin).
Q: How do you calculate the acceleration vector from position? A: Differentiate the position vector r(t) twice: a(t) = r''(t) = ?x''(t), y''(t), z''(t)?. Trap/Clarification: Forgetting to differentiate each component separately (e.g., treating r(t) as a scalar) is a common error.
Q: How do you find the tangential and normal components of acceleration? A: Use: - a_T = (v · a) / ?v? (tangential, changes speed) - a_N = ?v × a? / ?v? (normal, changes direction) Trap/Clarification: a_N is not the same as centripetal acceleration unless motion is circular (then a_N = v²/?, where ? is radius).
Q: Can speed be constant while acceleration is non-zero? A: Yes, if acceleration is purely normal (e.g., uniform circular motion), changing direction but not speed. Trap/Clarification: If a_T = 0 but a_N-0, speed is constant but acceleration exists.
Q: Can the velocity vector be zero while acceleration is non-zero? A: Yes, at a momentary stop (e.g., a ball at the peak of its trajectory), where v(t) = 0 but a(t) = g (gravity). Trap/Clarification: This is not the same as "no acceleration"—acceleration is the rate of change of velocity, not velocity itself.
Statement: If an object moves along a straight line, its acceleration vector must be parallel to its velocity vector. Answer: TRUE Why the common mistake happens: Students assume acceleration can have a perpendicular component even in straight-line motion (it can’t—a_N = 0).
Statement: The speed of an object is the derivative of the magnitude of its position vector. Answer: FALSE Why the common mistake happens: Students confuse d/dt ?r(t)? (rate of change of distance from origin) with ?v(t)? (path length per time).
Statement: If the velocity vector is constant, the acceleration vector must be zero. Answer: TRUE Why the common mistake happens: Students overcomplicate by considering "constant speed but changing direction" (which would require a_N-0). Constant velocity means no change in speed or direction.
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