By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Work-Energy Theorem is a fundamental principle that relates the net work done on an object to the change in its kinetic energy. It states that the net work done on an object is equal to the change in its kinetic energy.
This topic appears in exams to test your understanding of the relationship between work and energy, and to assess your ability to apply this principle to solve problems. The examiner wants to see if you can correctly identify the type of work (conservative or non-conservative) and apply the Work-Energy Theorem to solve problems.
This topic is tested in exams such as AP Physics, SAT Physics, and engineering entrance exams. It appears frequently, carrying around 20-30% of the total marks. The examiner is testing your ability to apply the Work-Energy Theorem to solve problems, which requires a deep understanding of the underlying concepts.
To master this topic, you need to understand the following core concepts:
Before tackling this topic, you need to understand the following prerequisites:
If you are missing these prerequisites, you may struggle to understand the Work-Energy Theorem and its applications.
The Work-Energy Theorem states that:
Net Work = ΔKE
Where ΔKE is the change in kinetic energy.
The theorem can be applied to both conservative and non-conservative forces.
Frequency: 30% Difficulty Rating: Intermediate Question Type or Real-World Task Type: Problem-solving, multiple-choice questions
Intermediate
To master this topic, you need to know the following rules, formulas, and principles:
Here are three worked examples that escalate in difficulty:
A 2 kg block is pulled 5 m along a horizontal surface by a force of 10 N. What is the change in kinetic energy of the block?
A 5 kg block is lifted 10 m vertically upwards by a force of 20 N. What is the change in kinetic energy of the block?
A 10 kg block is pushed 5 m along a horizontal surface by a force of 15 N. The block starts from rest and ends with a velocity of 2 m/s. What is the change in kinetic energy of the block?
Here are four common exam traps and mistakes to watch out for:
Here are some shortcut strategies and exam hacks to help you solve questions faster and more accurately:
Here are the four distinct question formats that this topic appears in across different exams:
Here are five multiple-choice questions at mixed difficulty levels:
A) 20 J B) 50 J C) 100 J D) 200 J
Correct answer: B) 50 J Explanation: The work done on the block is W = F × d = 10 N × 5 m = 50 J. Since the force is conservative, the work done is equal to the negative change in potential energy: W = -ΔPE. Therefore, ΔKE = -W = -50 J.Why the distractors are tempting: Options A and C are tempting because they are close to the correct answer, but option D is too large.
A) -100 J B) -200 J C) -300 J D) -400 J
Correct answer: B) -200 J Explanation: The work done on the block is W = F × d = 20 N × 10 m = 200 J. Since the force is conservative, the work done is equal to the negative change in potential energy: W = -ΔPE. Therefore, ΔKE = -W = -200 J.Why the distractors are tempting: Options A and C are tempting because they are close to the correct answer, but option D is too large.
A) 50 J B) 75 J C) 100 J D) 150 J
Correct answer: B) 75 J Explanation: The work done on the block is W = F × d = 15 N × 5 m = 75 J. Since the force is non-conservative, the work done is equal to the change in kinetic energy: W = ΔKE. Therefore, ΔKE = W = 75 J.Why the distractors are tempting: Options A and C are tempting because they are close to the correct answer, but option D is too large.
A 2 kg block is lifted 5 m vertically upwards by a force of 10 N. What is the change in potential energy of the block?
Correct answer: B) 50 J Explanation: The work done on the block is W = F × d = 10 N × 5 m = 50 J. Since the force is conservative, the work done is equal to the negative change in potential energy: W = -ΔPE. Therefore, ΔPE = -W = -50 J.Why the distractors are tempting: Options A and C are tempting because they are close to the correct answer, but option D is too large.
A 5 kg block is pushed 10 m along a horizontal surface by a force of 20 N. The block starts from rest and ends with a velocity of 3 m/s. What is the change in kinetic energy of the block?
A) 150 J B) 200 J C) 250 J D) 300 J
Correct answer: B) 200 J Explanation: The work done on the block is W = F × d = 20 N × 10 m = 200 J. Since the force is non-conservative, the work done is equal to the change in kinetic energy: W = ΔKE. Therefore, ΔKE = W = 200 J.Why the distractors are tempting: Options A and C are tempting because they are close to the correct answer, but option D is too large.
Here are the five things you must remember walking into the exam hall:
Here is the suggested study sequence to master this topic from scratch to exam-ready:
Here are three closely connected topics that appear alongside this one in exams:
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