By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Complete Guide for AP Calculus & Physics
"Mastering Faraday’s and Lenz’s Laws lets you predict how generators, transformers, and even wireless chargers work—and it’s worth 10–15% of your AP Physics C: E&M exam. Miss this, and you’ll lose easy points on free-response questions about changing magnetic fields. Let’s lock it down."
Formula: ε = - dΦ/dt - ε = Induced EMF (Volts, V) - Φ = Magnetic flux (Wb) = B · A · cosθ (B = magnetic field, A = area, θ = angle between B and normal to the loop) - dΦ/dt = Rate of change of flux (Wb/s) - MEMORISE THIS – Core formula for all induced EMF problems.
Formula: Φ = B · A · cosθ - B = Magnetic field strength (Tesla, T) - A = Area of the loop (m²) - θ = Angle between B and the normal (perpendicular) to the loop - MEMORISE THIS – Used to calculate flux before applying Faraday’s Law.
Formula: ε = B · L · v · sinθ - B = Magnetic field (T) - L = Length of the conductor (m) - v = Velocity of the conductor (m/s) - θ = Angle between v and B - MEMORISE THIS – Used when a rod or wire moves through a B-field.
Rule: - The induced current creates a magnetic field that opposes the change in flux. - Use the right-hand rule to determine direction: 1. Point thumb in direction of induced magnetic field (opposes change). 2. Fingers curl in direction of induced current.
Problem: A circular loop of radius 0.2 m is placed in a uniform magnetic field of 0.5 T. The field decreases to 0.1 T in 2 seconds. What is the induced EMF?
Solution:1. Flux equation: Φ = B · A · cosθ - A = πr² = π(0.2)² = 0.04π m² - θ = 0° (loop perpendicular to B), so cosθ = 1 - Initial Φ = 0.5 · 0.04π = 0.02π Wb - Final Φ = 0.1 · 0.04π = 0.004π Wb2. Change in flux: ΔΦ = Final Φ - Initial Φ = 0.004π - 0.02π = -0.016π Wb3. Rate of change of flux: dΦ/dt = ΔΦ / Δt = -0.016π / 2 = -0.008π Wb/s4. Faraday’s Law: ε = -dΦ/dt = -(-0.008π) = 0.008π V ≈ 0.025 V5. Lenz’s Law: - Flux is decreasing (B decreases). - Induced current creates a field in the same direction as original B (to oppose the decrease).
What we did and why: - Calculated flux before and after the change. - Used Faraday’s Law to find EMF from the rate of change. - Applied Lenz’s Law to confirm direction.
Problem: A square loop of side length 0.3 m is pulled out of a 0.4 T magnetic field at 0.5 m/s. The field is perpendicular to the loop. What is the induced EMF when half the loop is still in the field?
Solution:1. Flux depends on area inside B-field. - Total area = (0.3 m)² = 0.09 m² - Area still in field = 0.3 m × (0.15 m) = 0.045 m² (half the loop)2. Rate of change of area: - Loop is moving at 0.5 m/s, so dA/dt = -0.3 m × 0.5 m/s = -0.15 m²/s (negative because area is decreasing)3. Faraday’s Law: ε = -dΦ/dt = -B · (dA/dt) = -0.4 · (-0.15) = 0.06 V4. Lenz’s Law: - Flux is decreasing (loop leaving field). - Induced current creates a field into the page (same as original B).
What we did and why: - Recognized that flux changes because area changes. - Used dA/dt to find the rate of change. - Applied Faraday’s Law directly.
Problem: A metal rod of length 0.8 m slides on two parallel rails at 3 m/s in a 0.2 T magnetic field directed into the page. The rails are 0.5 m apart and connected by a resistor. What is the induced current in the resistor if its resistance is 4 Ω?
Solution:1. Motional EMF: ε = B · L · v · sinθ - B = 0.2 T, L = 0.8 m, v = 3 m/s, θ = 90° (v ⊥ B) - ε = 0.2 · 0.8 · 3 · sin90° = 0.48 V2. Current in circuit: I = ε / R = 0.48 V / 4 Ω = 0.12 A3. Direction (Lenz’s Law): - Flux into the page is increasing (rod moves right, area increases). - Induced current must create a field out of the page to oppose. - Right-hand rule: Thumb out of page → fingers curl counterclockwise. - Current flows up the rod.
What we did and why: - Used motional EMF formula for a moving conductor. - Calculated current using Ohm’s Law. - Applied Lenz’s Law to determine direction.
"Listen up—this is all you need to remember for Faraday’s and Lenz’s Laws:1. Flux = BAcosθ – If B, A, or θ changes, flux changes.2. Faraday’s Law: ε = -dΦ/dt – Take the derivative of flux. Negative sign = Lenz’s Law.3. Motional EMF: ε = BLvsinθ – For a rod moving in a B-field.4. Lenz’s Law direction – Induced current opposes the change. Use the right-hand rule.5. Watch for traps – Changing angles, partial areas, or combined EMF sources.
On the exam, write down the flux equation first. Then take the derivative. Finally, check direction with Lenz’s Law. You’ve got this!
Join 4M+ learners. Unlock unlimited quizzes, wrong-answer tracking, flashcards + reminders, study guides, and 1-on-1 challenges.