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The equilibrium constant (Kc) is a mathematical expression that describes the ratio of the concentrations of products to reactants at equilibrium. It is defined as:
Kc = [C]c [D]d / [A]a [B]b
where [C], [D], [A], and [B] are the concentrations of the products and reactants at equilibrium, and a, b, c, and d are their respective stoichiometric coefficients.
The equilibrium pressure (Kp) is a similar expression that describes the ratio of the partial pressures of products to reactants at equilibrium. It is defined as:
Kp = (Pc)^(c) (Pd)^(d) / (Pa)^(a) (Pb)^(b)
where Pc, Pd, Pa, and Pb are the partial pressures of the products and reactants at equilibrium.
Le Chatelier's Principle states that if a system at equilibrium is subjected to a change in concentration, pressure, or temperature, the equilibrium will shift in a direction that tends to counteract the change.
A reaction is represented by the equation:
2NO(g) + O2(g)-2NO2(g)
The equilibrium constant (Kc) is 0.5. If the concentration of NO is 0.2 M, calculate the concentration of NO2.
We can use the equilibrium expression to write:
Kc = [NO2]^2 / ([NO]^2 [O2])
Rearranging to solve for [NO2], we get:
[NO2] = sqrt(Kc [NO]^2 [O2])
Substituting the given values, we get:
[NO2] = sqrt(0.5 (0.2)^2 (1))
[NO2] = 0.2 M
N2(g) + 3H2(g)-2NH3(g)
The equilibrium pressure (Kp) is 10. If the partial pressure of N2 is 2 atm, calculate the partial pressure of NH3.
Kp = (P NH3)^2 / (P N2 (P H2)^3)
Rearranging to solve for P NH3, we get:
P NH3 = sqrt(Kp P N2 (P H2)^3)
P NH3 = sqrt(10 (2) (1)^3)
P NH3 = 3.16 atm
What is the equilibrium constant (Kc) for the reaction:
A) 0.5 B) 1.0 C) 2.0 D) 5.0
Correct answer: A) 0.5 Why the distractors fail: B) 1.0 is the equilibrium constant for a reaction at equilibrium, not the given reaction. C) 2.0 is the equilibrium constant for a reaction with a different stoichiometry. D) 5.0 is an arbitrary value that is not related to the given reaction.
A) 1.0 atm B) 2.0 atm C) 3.16 atm D) 5.0 atm
Correct answer: C) 3.16 atm Why the distractors fail: A) 1.0 atm is a low value that is not consistent with the given equilibrium pressure. B) 2.0 atm is the partial pressure of N2, not NH3. D) 5.0 atm is an arbitrary value that is not related to the given reaction.
What is the effect of increasing the concentration of a reactant on a chemical equilibrium?
A) The equilibrium will shift to the left. B) The equilibrium will shift to the right. C) The equilibrium will remain unchanged. D) The equilibrium will shift to the right and then to the left.
Correct answer: B) The equilibrium will shift to the right. Why the distractors fail: A) Increasing the concentration of a reactant will cause the equilibrium to shift to the right, not left. C) The equilibrium will not remain unchanged, it will shift to counteract the change in concentration. D) The equilibrium will not shift to the right and then to the left, it will only shift to the right.
CaCO3(s)-CaO(s) + CO2(g)
The equilibrium constant (Kc) is 10. If the concentration of CO2 is 0.1 M, calculate the concentration of CaO.
A) 0.01 M B) 0.1 M C) 1.0 M D) 10.0 M
Correct answer: A) 0.01 M Why the distractors fail: B) 0.1 M is the concentration of CO2, not CaO. C) 1.0 M is a high value that is not consistent with the given equilibrium constant. D) 10.0 M is an arbitrary value that is not related to the given reaction.
What is the unit of the equilibrium constant (Kc)?
A) M B) atm C) L/mol D) K
Correct answer: C) L/mol Why the distractors fail: A) M is the unit of concentration, not equilibrium constant. B) atm is the unit of pressure, not equilibrium constant. D) K is the unit of temperature, not equilibrium constant.
given the partial pressures of N2 and H2 are 2 atm and 1 atm, respectively.
Explain the effect of increasing the temperature on a chemical equilibrium.
Write the equilibrium expression for the reaction:
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