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Linear equations and inequalities form the backbone of CAT’s Quantitative Ability (QA) section. They appear in ~8-10% of QA questions (2-3 per paper) and are often low-hanging fruit—solvable in under 2 minutes with the right approach. Mastering them boosts accuracy and frees up time for tougher problems.
Real-CAT Style Example:"If (3x + 4y = 12) and (5x - 2y = 8), what is the value of (x + y)?" (This tests substitution/elimination, a core skill for linear equations.)
When to use: When one equation is easily solvable for one variable (e.g., (y = 2x + 3)).
Elimination Method
When to use: When coefficients are simple (e.g., (2x + 3y = 5) and (4x - 3y = 1)).
Graphical Interpretation
When to use: For word problems involving "break-even" or "intersection" scenarios.
Inequality Sign Rules
When to use: Solving inequalities like (-2x + 3 > 7).
Modulus Equations
When to use: Absolute value equations/inequalities.
Word Problem Translation
When to use: Age, mixture, or work-rate problems.
Option Elimination (MCQs)
Question:If (2x + 3y = 12) and (4x - y = 5), what is the value of (x - y)?
Solution (Using Elimination):1. Multiply the second equation by 3 to align (y) coefficients: (12x - 3y = 15).2. Add to the first equation: ((2x + 3y) + (12x - 3y) = 12 + 15) → (14x = 27) → (x = \frac{27}{14}).3. Substitute (x) into the second equation: (4(\frac{27}{14}) - y = 5) → (\frac{108}{14} - y = 5) → (y = \frac{108}{14} - \frac{70}{14} = \frac{38}{14} = \frac{19}{7}).4. Calculate (x - y): (\frac{27}{14} - \frac{19}{7} = \frac{27}{14} - \frac{38}{14} = -\frac{11}{14}).
Answer: (-\frac{11}{14}).
(Note: For MCQs, plugging options would be faster!)
Mistake: Forgetting to reverse the inequality sign when multiplying/dividing by a negative. Why it happens: Overlooking the sign change rule. Correct approach: Always check the sign of the coefficient before solving.
Mistake: Solving for (x) but not substituting back to find (y). Why it happens: Rushing through steps. Correct approach: Always find both variables unless the question asks for a combination (e.g., (x + y)).
Mistake: Misinterpreting modulus equations (e.g., (|x| = -3) has no solution). Why it happens: Assuming absolute value always yields two solutions. Correct approach: Remember (|x| \geq 0)—no solution if RHS is negative.
Mistake: Incorrectly translating word problems (e.g., "5 more than twice a number" → (2x + 5), not (5 + 2x)). Why it happens: Misordering terms. Correct approach: Write the equation step-by-step (e.g., "twice a number" → (2x), "5 more than" → (+5)).
Avoid: Always check consistency before solving.
Trap: Inequalities with modulus (e.g., (|x - 2| < 3) → (-3 < x - 2 < 3)).
Avoid: Split into two cases only if the inequality is (|x - 2| > 3).
Time Guide:
Question: If (3x - 2y = 7) and (x + y = 5), what is (x)? Answer: (x = 3) (Substitute (y = 5 - x) into the first equation).
Question: Solve (|2x - 1| \leq 5). Answer: (-2 \leq x \leq 3) (Split into (-5 \leq 2x - 1 \leq 5)).
Final Tip: For CAT, speed > perfection. If a question takes >2.5 minutes, mark it and move on. Linear equations are your safety net—master them!
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