Balancing of Reciprocating Masses topics include: Primary unbalanced forces for reciprocating masses, locomatives balancing, tractive force, swaying couple, multi cylinder inline and v-engines. Balancing of reciprocating masses is a mechanical engineering process that involves distributing the weight of all components in a machine evenly.  The purpose of balancing is to: Reduce vibrations Ensure smooth operation of rotating machinery Minimize dynamic forces and moments Prevent excessive wear, noise, and structural failure  An imbalance in these masses can lead to machine failure,... Show more

Balancing of Reciprocating Masses topics include: Primary unbalanced forces for reciprocating masses, locomatives balancing, tractive force, swaying couple, multi cylinder inline and v-engines.

Balancing of reciprocating masses is a mechanical engineering process that involves distributing the weight of all components in a machine evenly. 

The purpose of balancing is to:
Reduce vibrations
Ensure smooth operation of rotating machinery
Minimize dynamic forces and moments
Prevent excessive wear, noise, and structural failure 

An imbalance in these masses can lead to machine failure, causing unwanted vibrations and noisy operation. 
To balance reciprocating masses, you can add another mass that generates the same force as the disturbing force, which is the centrifugal force. The new mass should be placed exactly 180 degrees opposite the original mass. 
Balancing reciprocating masses can be achieved by adding balancing masses at specific locations on the rotating parts of the machine. These balancing masses are calculated based on the magnitude and direction of the unbalanced forces and moments. 

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Machine Dynamics Practice Test: Balancing of Reciprocating Masses

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25 Questions

1. Find the maximum value of swaying couple in newtons from the following data:
m = 100Kg
ω = 300 rpm
radius = 0.6m
c = 2/3
a = 2\(\sqrt{2}\)m

6978737465687574

2. In an inside cylinder locomotive, the position of the driving wheels is _________

Inside cylinderOutside cylinderDown to cylinderAbove the cylinder

3. From the following data of a 60 degree V-twin engine, determine the minimum value for primary forces in newtons:
Reciprocating mass per cylinder = 1.5 Kg
Stroke length = 10 cm
Length of connecting rod = 25 cm
Engine speed = 2500 rpm

2570454677118764

4. A V-twin engine has the cylinder axes at 90 degrees and the connecting rods operate a common crank. The reciprocating mass per cylinder is 11.5 kg and the crank radius is 7.5 cm. The length of the connecting rod is 0.3 m. If the engine is rotating at the speed is 500 r.p.m. What is the value of maximum resultant secondary force in Newtons?

736636836936

5. The swaying couple is due to the

two cylinders of locomotivepartial balancingsecondary unbalanced forceprimary unbalanced force

6. Which of the following has a tendency to sway engine in alternately in clockwise and anticlockwise directions?

Hammer coupleTractive forceSwaying coupleHammer blow

7. What is the effect of partial balancing of the reciprocating parts?

Balanced secondary forceUnbalanced primary forceBalanced primary forceUnbalanced secondary force

8. The tractive force is maximum or minimum when the angle of inclination of the crank to the line of stroke ( θ ) is equal to

135° and 180°90° and 225°135° and 315°180° and 225°

9. At which of the following angles in degrees does the swaying couple attains a maximum value?

604590135

10. This couple has swaying effect about a horizontal axis.

MaybeTrueDon't KnowFalse

11. Find the maximum value of swaying couple in newtons from the following data:
m = 200Kg
ω = 300 rpm
radius = 0.6m
c = 2/3
a = 2\(\sqrt{2}\)m

17374139561757416568

12. In a locomotive, the maximum magnitude of the unbalanced force along the perpendicular to the line of stroke, is known as

hammer blownone of theseswaying coupletractive force

13. Find the minimum value of swaying couple in newtons from the following data:
m = 100Kg
ω = 300 rpm
radius = 0.6m
c = 2/3
a = 2\(\sqrt{2}\)m

-6978-6568-7574- 7374

14. From the following data of a 60 degree V-twin engine, determine the maximum value for primary forces in newtons:
Reciprocating mass per cylinder = 1.5 Kg
Stroke length = 10 cm
Length of connecting rod = 25 cm
Engine speed = 2500 rpm

7711454625088764

15. In the given figure, the locomotive is a 4 cylinder locomotive.

FalseTrueDon't knowMaybe

16. Identify the type of locomotive from the given figure.

Bottom cylinderTop cylinderOutside cylinderInside cylinder

17. For a V-twin engine, which of the following means can be used to balance the primary forces?

Revolving balance massRotating balance massReciprocating balance massBy the means of secondary forces

18. For a two cylinder locomotives, the crank are placed at right angles to each other.

TrueMaybeFalseDon't Know

19. At which of the following angles in degrees does the tractive force attains a minimum value?

609045315

20. The effect of an unbalanced primary force perpendicular to the line of stroke is to produce _____

Variation in pressure on the railsSwaying coupleVariation in tractive forcePiston effort

21. Find the variation in tractive force in newtons from the following data:
m = 100Kg
ω = 300 rpm
radius = 0.6m
c = 2/3

16568173741395617574

22. The swaying couple is maximum or minimum when the angle of inclination of the crank to the line of stroke ( θ ) is equal to

135° and 225°90° and 135°45° and 135°45° and 225°

23. From the following data of a 60 degree V-twin engine, determine the maximum value for secondary forces in newtons:
Reciprocating mass per cylinder = 1.5 Kg
Stroke length = 10 cm
Length of connecting rod = 25 cm
Engine speed = 2500 rpm

890.3760.4970.6580.3

24. The partial balancing means

balancing partially the revolving massesall of thesebalancing partially the reciprocating massesbest balancing of engines

25. Swaying couple attains a maxima or minima when the crank angle is 45 degrees.

TrueFalseDon't KnowMaybe