By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Complete Guide for GCSE/A-Level Biology
"Mastering respiration unlocks 10–15% of your GCSE/A-Level Biology exam—including the infamous 6-mark ATP yield question. One wrong step here costs you easy marks. Today, you’ll learn the exact method to calculate ATP, track carbon atoms, and explain every stage like a pro."
MEMORISE THIS: - Glycolysis: 2 ATP (net) - Krebs: 2 ATP - ETC: 26–28 ATP (from NADH/FADH₂)
Sketch this every time:
Glucose (6C) ↓ Glycolysis (Cytoplasm) 2 Pyruvate (3C) + 2 ATP + 2 NADH ↓ Link Reaction (Mitochondrial Matrix) 2 Acetyl-CoA (2C) + 2 CO₂ + 2 NADH ↓ Krebs Cycle (Matrix) 4 CO₂ + 2 ATP + 6 NADH + 2 FADH₂ ↓ ETC (Inner Membrane) ~26–28 ATP + H₂O
Check: 6C in → 6 CO₂ out.
MEMORISE: 30 ATP (eukaryotes), 32 ATP (prokaryotes).
Question: Calculate the total ATP yield from 1 glucose molecule in a eukaryotic cell.
Solution: 1. Glycolysis: 2 ATP + 2 NADH 2. Link Reaction: 2 NADH 3. Krebs Cycle: 2 ATP + 6 NADH + 2 FADH₂ 4. ETC: - 10 NADH × 2.5 ATP = 25 ATP - 2 FADH₂ × 1.5 ATP = 3 ATP 5. Total: 25 + 3 + 4 (substrate-level) = 30 ATP
What we did and why: Added ATP from all stages, converted NADH/FADH₂ to ATP using standard values.
Question: A student says, "In the Krebs cycle, 6 CO₂ are released per glucose." Explain why this is incorrect.
Solution: 1. Krebs cycle runs twice per glucose (once per Acetyl-CoA). 2. Each cycle releases 2 CO₂. 3. Total CO₂ from Krebs: 2 × 2 = 4 CO₂. 4. Link reaction releases 2 CO₂. 5. Total CO₂ per glucose: 4 + 2 = 6 CO₂ (but Krebs alone = 4 CO₂).
What we did and why: Separated CO₂ from link reaction vs. Krebs to show the student’s error.
Question: A mutant yeast strain produces only FADH₂ (no NADH). How many ATP can it make from 1 glucose? Assume 1 FADH₂ = 1.5 ATP.
Solution: 1. Glycolysis: 0 NADH, 0 FADH₂ (but 2 ATP net). 2. Link Reaction: 0 NADH, 0 FADH₂. 3. Krebs Cycle: 0 NADH, 2 FADH₂. 4. ETC: 2 FADH₂ × 1.5 ATP = 3 ATP. 5. Add substrate-level ATP: 2 (glycolysis) + 2 (Krebs) = 4 ATP. 6. Total: 3 + 4 = 7 ATP.
What we did and why: Ignored NADH, focused on FADH₂ and substrate-level ATP.
Mistake: Counting 3 ATP per NADH (prokaryote value) in eukaryotes. Why it happens: Confusing prokaryote/eukaryote ATP yields. Correct approach: Use 2.5 ATP per NADH for eukaryotes.
Mistake: Forgetting substrate-level ATP (only counting ETC). Why it happens: Overlooking ATP made in glycolysis/Krebs. Correct approach: Add 4 ATP (2 glycolysis + 2 Krebs).
Mistake: Saying "6 CO₂ from Krebs." Why it happens: Not accounting for link reaction CO₂. Correct approach: Krebs = 4 CO₂; link reaction = 2 CO₂.
Mistake: Misplacing stages (e.g., ETC in cytoplasm). Why it happens: Not memorising locations. Correct approach: Glycolysis = cytoplasm; rest = mitochondria.
Mistake: Ignoring the "net" ATP in glycolysis. Why it happens: Counting 4 ATP (gross) instead of 2 ATP (net). Correct approach: Glycolysis uses 2 ATP, makes 4 → net 2 ATP.
Total: 11.5 + 1 (substrate-level) = 12.5 ATP per pyruvate.
Trap: "Explain why ATP yield varies." How to spot it: Question asks for reasons, not a number. How to avoid it:
Leaky membranes (H⁺ gradient not 100% efficient).
Trap: "Describe the role of oxygen." How to spot it: Vague question about ETC. How to avoid it:
"Here’s the night-before cheat sheet: 1. Glycolysis: 2 ATP net, 2 NADH, 0 CO₂. Happens in cytoplasm. 2. Link Reaction: 2 NADH, 2 CO₂. Pyruvate → Acetyl-CoA. 3. Krebs Cycle: 2 ATP, 6 NADH, 2 FADH₂, 4 CO₂. Runs twice per glucose. 4. ETC: 10 NADH × 2.5 = 25 ATP; 2 FADH₂ × 1.5 = 3 ATP. Total 30 ATP. 5. Carbon: 6C in → 6 CO₂ out. Track it! 6. Exam traps: Watch for ‘per pyruvate,’ ‘why ATP varies,’ and oxygen’s role. Draw the diagram, count the ATP, and you’ve got this!"
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