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Study Guide: A Level Chemistry - How to Solve: Acid-Base Titrations & Back Titrations (pH Curves, Indicators)
Source: https://www.fatskills.com/gcse-chemistry/chapter/a-level-chemistry-how-to-solve-acid-base-titrations-back-titrations-ph-curves-indicators

A Level Chemistry - How to Solve: Acid-Base Titrations & Back Titrations (pH Curves, Indicators)

By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.

⏱️ ~5 min read

How to Solve: Acid-Base Titrations & Back Titrations (pH Curves, Indicators)

Complete Guide For GCSE/A-Level Chemistry (Edexcel, AQA, OCR, IB)


Introduction

"Mastering titrations unlocks 10–15% of your GCSE/A-Level Chemistry exam—think buffer calculations, drug purity tests, and even how your stomach neutralises acid. One wrong step? You lose 4–6 marks. Today, we’ll turn this into a 100% predictable process."


WHAT YOU NEED TO KNOW FIRST

  1. Moles & Concentration: n = c × V (moles = concentration × volume in dm³).
  2. pH Scale: Acids (pH < 7), bases (pH > 7), neutral (pH = 7).
  3. Strong vs. Weak Acids/Bases: Strong = fully dissociates (e.g., HCl, NaOH); weak = partially dissociates (e.g., CH₃COOH, NH₃).

KEY TERMS & FORMULAS

Terms

Term Definition
Titration Lab technique to find unknown concentration using a known solution.
Back Titration Adding excess acid/base, then titrating the leftover to find the original amount.
Equivalence Point Point where moles of acid = moles of base (pH jump on curve).
Endpoint Point where indicator changes colour (should match equivalence point).
pH Curve Graph of pH vs. volume of titrant added.

Formulas

  1. Moles (n) = concentration (c) × volume (V)
  2. c = mol/dm³, V = dm³ (MEMORISE THIS).
  3. If volume is in cm³, divide by 1000 first.

  4. Dilution: c₁V₁ = c₂V₂

  5. Used when diluting solutions (MEMORISE THIS).

  6. % Purity = (mass of pure substance / mass of impure sample) × 100

  7. Used in back titrations (MEMORISE THIS).

  8. pH = -log[H⁺]

  9. For strong acids only (given on exam sheet).

STEP-BY-STEP METHOD

Part 1: Standard Titration (Direct)

Goal: Find unknown concentration of acid/base.

  1. Write the balanced equation (e.g., HCl + NaOH → NaCl + H₂O).
  2. Calculate moles of known solution (use n = c × V).
  3. V must be in dm³ (divide cm³ by 1000).
  4. Use mole ratio to find moles of unknown.
  5. E.g., 1:1 ratio → moles of acid = moles of base.
  6. Calculate unknown concentration (use c = n / V).
  7. Check units: Answer must be in mol/dm³.

Part 2: Back Titration

Goal: Find % purity or concentration when direct titration is impossible (e.g., insoluble sample).

  1. Write two balanced equations:
  2. Reaction of sample with excess acid/base.
  3. Titration of leftover acid/base.
  4. Calculate moles of titrant used (e.g., NaOH in burette).
  5. Find moles of leftover acid/base (use mole ratio from 2nd equation).
  6. Find moles of acid/base that reacted with sample (initial moles – leftover moles).
  7. Use 1st equation’s mole ratio to find moles of sample.
  8. Calculate mass or % purity (use mass = n × Mᵣ).

Part 3: Choosing Indicators

  1. Identify equivalence point pH from pH curve:
  2. Strong acid + strong base → pH 7.
  3. Weak acid + strong base → pH > 7.
  4. Strong acid + weak base → pH < 7.
  5. Pick indicator with pH range overlapping equivalence point:
  6. Methyl orange: pH 3.1–4.4 (strong acid + weak base).
  7. Phenolphthalein: pH 8.3–10.0 (weak acid + strong base).

WORKED EXAMPLES

Example 1 – Basic Titration

Question: 25.0 cm³ of NaOH neutralises 20.0 cm³ of 0.100 mol/dm³ HCl. Find [NaOH].

Steps:
1. Balanced equation: HCl + NaOH → NaCl + H₂O (1:1 ratio).
2. Moles HCl = 0.100 × (20.0/1000) = 0.00200 mol.
3. Moles NaOH = 0.00200 mol (1:1 ratio).
4. [NaOH] = 0.00200 / (25.0/1000) = 0.0800 mol/dm³.

What we did and why: - Used n = c × V to find moles of HCl. - 1:1 ratio → moles NaOH = moles HCl. - Rearranged c = n / V to find [NaOH].


Example 2 – Medium (Back Titration)

Question: 2.50 g of impure CaCO₃ is reacted with 50.0 cm³ of 1.00 mol/dm³ HCl. Excess HCl requires 25.0 cm³ of 0.500 mol/dm³ NaOH for neutralisation. Find % purity of CaCO₃.

Steps:
1. Equations: - CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂ - HCl + NaOH → NaCl + H₂O
2. Moles NaOH = 0.500 × (25.0/1000) = 0.0125 mol.
3. Moles excess HCl = 0.0125 mol (1:1 ratio).
4. Initial moles HCl = 1.00 × (50.0/1000) = 0.0500 mol.
5. Moles HCl reacted with CaCO₃ = 0.0500 – 0.0125 = 0.0375 mol.
6. Moles CaCO₃ = 0.0375 / 2 = 0.01875 mol (1:2 ratio).
7. Mass CaCO₃ = 0.01875 × 100.1 = 1.877 g.
8. % purity = (1.877 / 2.50) × 100 = 75.1%.

What we did and why: - Used back titration to find moles of HCl that reacted with CaCO₃. - 1:2 ratio → moles CaCO₃ = ½ moles HCl. - Calculated mass and % purity.


Example 3 – Exam-Style (pH Curve + Indicator)

Question: A student titrates 0.100 mol/dm³ CH₃COOH with 0.100 mol/dm³ NaOH. Sketch the pH curve and choose the best indicator.

Steps:
1. pH curve features: - Starts at pH ~3 (weak acid). - Equivalence point at pH ~8.5 (weak acid + strong base). - Gradual rise, then sharp jump at equivalence point.
2. Indicator choice: - Phenolphthalein (pH 8.3–10.0) overlaps equivalence point. - Methyl orange (pH 3.1–4.4) is wrong (too low).

What we did and why: - Weak acid + strong base → equivalence point > pH 7. - Phenolphthalein matches the pH jump.


COMMON MISTAKES

  1. MISTAKE: Using cm³ directly in n = c × V. WHY IT HAPPENS: Forgetting to convert to dm³. CORRECT APPROACH: Divide cm³ by 1000 first.

  2. MISTAKE: Ignoring mole ratios. WHY IT HAPPENS: Assuming 1:1 ratio for all reactions. CORRECT APPROACH: Write balanced equation first.

  3. MISTAKE: Choosing wrong indicator. WHY IT HAPPENS: Not checking equivalence point pH. CORRECT APPROACH: Match indicator range to equivalence point.

  4. MISTAKE: Misreading burette. WHY IT HAPPENS: Reading from top instead of bottom of meniscus. CORRECT APPROACH: Always read at eye level, bottom of meniscus.

  5. MISTAKE: Not rinsing pipette/burette. WHY IT HAPPENS: Contamination from previous solutions. CORRECT APPROACH: Rinse with solution to be used.


EXAM TRAPS

  1. TRAP: Back titration with two different mole ratios. HOW TO SPOT IT: Two equations given (e.g., 1:1 and 1:2). HOW TO AVOID IT: Label each step clearly.

  2. TRAP: Dilution before titration. HOW TO SPOT IT: "25 cm³ of solution was diluted to 250 cm³". HOW TO AVOID IT: Use c₁V₁ = c₂V₂ to find new concentration.

  3. TRAP: pH curve with two equivalence points. HOW TO SPOT IT: Diprotic acid (e.g., H₂SO₄) or carbonate (CO₃²⁻). HOW TO AVOID IT: Identify all possible reactions.


1-MINUTE RECAP

"Here’s the night-before cheat sheet:
1.
Direct titration: Write equation → find moles of known → use ratio → find unknown concentration.
2.
Back titration: Two equations → find leftover moles → subtract → use ratio → find purity.
3.
Indicators: Strong acid + strong base = pH 7 (any indicator). Weak acid + strong base = pH > 7 (phenolphthalein). Strong acid + weak base = pH < 7 (methyl orange).
4.
pH curves: Sketch the jump—sharp for strong, gradual for weak.
5.
Units: Always dm³ for volume in n = c × V. Now go ace that exam!"