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"Mastering equilibrium constants lets you predict how far a reaction goes—whether it’s the Haber process making fertiliser or your lungs exchanging oxygen. On A-Level exams, this topic is worth 10-15% of your marks in chemistry papers. Get it right, and you’re one step closer to an A."
Before diving in, ensure you understand: 1. Dynamic equilibrium – Forward and reverse reactions occur at the same rate; concentrations remain constant. 2. Mole ratios – Coefficients in balanced equations tell you the ratio of reactants to products. 3. Ideal gas law basics – For Kp, you’ll need to relate pressure to moles (PV = nRT).
Formula: [ K_c = \frac{[C]^c [D]^d}{[A]^a [B]^b} ] - [A], [B] = Concentrations of reactants (mol/dm³) - [C], [D] = Concentrations of products (mol/dm³) - a, b, c, d = Coefficients from the balanced equation - MEMORISE THIS: Only gases and aqueous solutions appear in Kc. Solids and pure liquids are excluded.
Formula: [ K_p = \frac{(P_C)^c (P_D)^d}{(P_A)^a (P_B)^b} ] - P_A, P_B = Partial pressures of reactants (atm or kPa) - P_C, P_D = Partial pressures of products (atm or kPa) - MEMORISE THIS: Only gases appear in Kp. Solids, liquids, and aqueous solutions are excluded.
Formula: [ P_A = \text{Mole fraction of A} \times \text{Total pressure} ] [ \text{Mole fraction of A} = \frac{\text{Moles of A}}{\text{Total moles of gas}} ] - Given on exam sheet: Usually provided, but memorise the concept.
Formula: [ K_p = K_c (RT)^{\Delta n} ] - R = Gas constant (0.0821 dm³·atm·mol⁻¹·K⁻¹ or 8.314 J·mol⁻¹·K⁻¹) - T = Temperature (Kelvin) - Δn = Moles of gaseous products – moles of gaseous reactants - MEMORISE THIS: Only needed if the question asks for conversion.
Question: For the reaction ( H_2(g) + I_2(g) \rightleftharpoons 2HI(g) ), at equilibrium, [H₂] = 0.20 M, [I₂] = 0.20 M, and [HI] = 0.80 M. Calculate Kc.
Solution: 1. Balanced equation: ( H_2 + I_2 \rightleftharpoons 2HI ) 2. Kc expression: ( K_c = \frac{[HI]^2}{[H_2][I_2]} ) 3. Substitute values: ( K_c = \frac{(0.80)^2}{(0.20)(0.20)} ) 4. Calculate: ( K_c = \frac{0.64}{0.04} = 16 )
What we did and why: We used the equilibrium concentrations directly in the Kc expression. No ICE table was needed because all equilibrium concentrations were given.
Question: For ( N_2O_4(g) \rightleftharpoons 2NO_2(g) ), initial [N₂O₄] = 0.50 M. At equilibrium, [NO₂] = 0.60 M. Calculate Kc.
Solution: 1. Balanced equation: ( N_2O_4 \rightleftharpoons 2NO_2 ) 2. ICE table: | Species | Initial (M) | Change (M) | Equilibrium (M) | |---------|-------------|------------|------------------| | N₂O₄ | 0.50 | -x | 0.50 - x | | NO₂ | 0 | +2x | 2x | 3. Given [NO₂] at equilibrium = 0.60 M, so 2x = 0.60 → x = 0.30 M. 4. [N₂O₄] at equilibrium = 0.50 - 0.30 = 0.20 M. 5. Kc expression: ( K_c = \frac{[NO_2]^2}{[N_2O_4]} ) 6. Substitute: ( K_c = \frac{(0.60)^2}{0.20} = \frac{0.36}{0.20} = 1.8 )
What we did and why: We used an ICE table to find the change in concentration. Since [NO₂] was given, we worked backward to find x and then [N₂O₄].
Question: For ( 2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g) ), at equilibrium, the mixture contains 0.40 mol SO₂, 0.20 mol O₂, and 0.60 mol SO₃ in a 2.0 dm³ vessel at 500 K. Total pressure = 1.5 atm. Calculate Kp.
Solution: 1. Balanced equation: ( 2SO_2 + O_2 \rightleftharpoons 2SO_3 ) 2. Find mole fractions: - Total moles = 0.40 + 0.20 + 0.60 = 1.20 mol - Mole fraction SO₂ = 0.40 / 1.20 = 1/3 - Mole fraction O₂ = 0.20 / 1.20 = 1/6 - Mole fraction SO₃ = 0.60 / 1.20 = 1/2 3. Calculate partial pressures: - ( P_{SO_2} = (1/3) \times 1.5 = 0.50 ) atm - ( P_{O_2} = (1/6) \times 1.5 = 0.25 ) atm - ( P_{SO_3} = (1/2) \times 1.5 = 0.75 ) atm 4. Kp expression: ( K_p = \frac{(P_{SO_3})^2}{(P_{SO_2})^2 (P_{O_2})} ) 5. Substitute: ( K_p = \frac{(0.75)^2}{(0.50)^2 (0.25)} = \frac{0.5625}{0.0625} = 9.0 )
What we did and why: We converted moles to mole fractions, then to partial pressures. Kp only uses gases, so we ignored any solids/liquids (none here).
CORRECT APPROACH: Exclude solids and pure liquids from the expression.
MISTAKE: Forgetting to raise concentrations/pressures to the power of their coefficients.
CORRECT APPROACH: Always check coefficients and apply them as exponents.
MISTAKE: Using initial concentrations instead of equilibrium concentrations in Kc.
CORRECT APPROACH: Only use equilibrium values in Kc/Kp.
MISTAKE: Mixing up Kc and Kp units.
CORRECT APPROACH: Kc is unitless (unless specified), Kp uses atm or kPa.
MISTAKE: Assuming Kc = Kp without conversion.
HOW TO AVOID IT: Always set up an ICE table to find equilibrium concentrations.
TRAP: Using pressure in Kc or concentration in Kp.
HOW TO AVOID IT: Convert pressure to concentration (or vice versa) using PV = nRT if needed.
TRAP: Changing temperature and asking for Kc/Kp.
"Here’s the night-before cheat sheet: 1. Kc uses concentrations (mol/dm³), Kp uses partial pressures (atm/kPa). 2. Only gases and aqueous solutions go in the expression—solids and liquids are out. 3. ICE tables are your best friend. Use them to track changes in concentration or moles. 4. Partial pressure = mole fraction × total pressure. Mole fraction = moles of gas / total moles. 5. Check units! Kc is usually unitless, Kp uses pressure units. 6. If temperature changes, K changes. If not, K stays the same. 7. Common mistakes: Forgetting exponents, mixing up Kc and Kp, or including solids. Double-check every step. Now go ace that exam!"
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