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12 + 22 ... + x2 = 1/6 [x(x+1)(2x+1)]. What is 12 + 32 +... + 152?

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1<sup>2</sup> + 2<sup>2</sup> ... + x<sup>2</sup> = 1/6 [x(x+1)(2x+1)]. What is 1<sup>2</sup> + 3<sup>2</sup> +... + 15<sup>2</sup>?






 
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