By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Introduction Mastering electromagnetic waves unlocks 10-12 marks in NEET Physics—enough to push you from a 150 to a 160+ score. These waves power MRI scans, Wi-Fi, and even the sunlight that keeps us alive. If you can solve Maxwell’s equations and predict wave behavior, you’ll ace both theory and numerical questions in the exam.
Before diving in, ensure you understand: 1. Electric and Magnetic Fields – How charges create fields, and how fields exert forces. 2. Faraday’s Law of Induction – Changing magnetic flux induces an electric field. 3. Ampere’s Circuital Law – Steady currents produce magnetic fields.
If any of these are unclear, pause and review them first—this topic builds directly on them.
Key Takeaway: - The last term (ε₀ dΦ_E/dt) is displacement current—it’s not a real current but behaves like one in Maxwell’s equations. - MEMORISE: Displacement current = ε₀ × (Rate of change of electric flux)
Formula: I_d = ε₀ (dΦ_E / dt)
What it means: - Even in empty space (no charges), a changing electric field creates a magnetic field—just like a real current would. -Example: In a charging capacitor, no current flows between plates, but the changing electric field acts like a current (displacement current).
Formula: c = 1 / √(μ₀ ε₀)
What it means: - All electromagnetic waves (light, radio, X-rays) travel at speed c = 3 × 10⁸ m/s in vacuum. - Given on exam sheet: μ₀ = 4π × 10⁻⁷ T m/A, ε₀ = 8.85 × 10⁻¹² C²/N m²
MEMORISE: - Frequency ↑ → Wavelength ↓ → Energy ↑ - Order: Radio → Microwave → Infrared → Visible → UV → X-ray → Gamma (RMI VUX G)
Problem: A parallel-plate capacitor has plates of area 2 m². The electric field between them changes at 5 × 10¹² V/m s. Find the displacement current.
Solution: 1. Given: - Area (A) = 2 m² - dE/dt = 5 × 10¹² V/m s 2. Formula: - Displacement current, I_d = ε₀ (dΦ_E / dt) - Electric flux, Φ_E = E × A - So, dΦ_E/dt = A × dE/dt 3. Plug in: - I_d = ε₀ × A × dE/dt - I_d = (8.85 × 10⁻¹²) × 2 × (5 × 10¹²) - I_d = 8.85 × 10⁻¹² × 10¹³ = 88.5 A 4. Answer: 88.5 A
What we did and why: - We used displacement current formula because the electric field is changing (no real current flows in a capacitor). - Key step: Recognizing that dΦ_E/dt = A × dE/dt for a uniform field.
Problem: An EM wave has E = 600 V/m and B = 2 × 10⁻⁶ T. Find its speed.
Solution: 1. Given: - E = 600 V/m - B = 2 × 10⁻⁶ T 2. Formula: - For EM waves, E = c × B - So, c = E / B 3. Plug in: - c = 600 / (2 × 10⁻⁶) = 3 × 10⁸ m/s 4. Answer: 3 × 10⁸ m/s (matches speed of light)
What we did and why: - We used the relationship between E and B in an EM wave (E = cB). - Key step: Recognizing that c = E/B is a quick way to find speed.
Problem: A radio station broadcasts at λ = 300 m. What is its frequency? (c = 3 × 10⁸ m/s)
Solution: 1. Given: - λ = 300 m - c = 3 × 10⁸ m/s 2. Formula: - c = f × λ - So, f = c / λ 3. Plug in: - f = (3 × 10⁸) / 300 = 1 × 10⁶ Hz = 1 MHz 4. Answer: 1 MHz
What we did and why: - We used the wave equation (c = fλ) to find frequency. - Key step: Unit check – 1 MHz is a reasonable frequency for radio waves.
"Listen up—this is all you need to remember for EM waves in NEET:
Ampere-Maxwell: Changing E → B field (displacement current!)
Displacement current = ε₀ × (dΦ_E/dt). Not a real current—just a changing electric field acting like one.
Speed of light (c) = 3 × 10⁸ m/s = 1/√(μ₀ ε₀). All EM waves travel at c in vacuum.
EM spectrum order: RMI VUX G (Radio → Microwave → Infrared → Visible → UV → X-ray → Gamma). Frequency ↑ → Wavelength ↓ → Energy ↑.
Key formulas:
If you see a capacitor in the question, think displacement current. If you see E and B, think c = E/B. If you see wavelength, think c = fλ.
Now go crush that exam!
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