By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Introduction Mastering nuclei unlocks 10-12 marks in NEET UG—enough to push you from a 600 to a 650+ score. It’s the difference between a medical seat and a waitlist. Plus, it explains nuclear power, cancer treatment, and how stars shine—real-world impact you’ll see in both physics and chemistry.
( N ) = Number of undecayed nuclei MEMORISE THIS
Decay law: ( N = N_0 e^{-\lambda t} )
Time for half the nuclei to decay. Formula: ( t_{1/2} = \frac{\ln 2}{\lambda} = \frac{0.693}{\lambda} ) MEMORISE THIS
Relation to decay constant: ( \lambda = \frac{0.693}{t_{1/2}} )
( c ) = Speed of light (3 × 10⁸ m/s) Given on exam sheet, but know how to use it
Mass defect (Δm): ( \Delta m = Zm_p + (A-Z)m_n - M_{\text{nucleus}} )
Problem: The half-life of ( ^{14}C ) is 5730 years. What fraction remains after 11460 years?
Step 1: Identify problem type → Half-life decay. Step 2: Given: - ( t_{1/2} = 5730 ) years - ( t = 11460 ) years Step 3: Use ( N = N_0 \left( \frac{1}{2} \right)^{t/t_{1/2}} ) Step 4: ( \frac{t}{t_{1/2}} = \frac{11460}{5730} = 2 ) - ( N = N_0 \left( \frac{1}{2} \right)^2 = \frac{N_0}{4} ) Step 5: Fraction remaining = ( \frac{1}{4} ).
What we did and why: We used the half-life formula directly because the time given was an exact multiple of the half-life. No need for decay constant here.
Problem: A sample has ( 10^{12} ) radioactive nuclei with ( \lambda = 0.01 ) s⁻¹. What is its activity after 100 s?
Step 1: Identify problem type → Decay law + activity. Step 2: Given: - ( N_0 = 10^{12} ) - ( \lambda = 0.01 ) s⁻¹ - ( t = 100 ) s Step 3: First, find remaining nuclei: - ( N = N_0 e^{-\lambda t} = 10^{12} e^{-0.01 \times 100} = 10^{12} e^{-1} ) - ( e^{-1} \approx 0.3679 ) - ( N \approx 3.679 \times 10^{11} ) Step 4: Activity ( A = \lambda N = 0.01 \times 3.679 \times 10^{11} = 3.679 \times 10^9 ) Bq. Step 5: Final answer: ( 3.68 \times 10^9 ) Bq (rounded to 3 sig. figs).
What we did and why: We first found the remaining nuclei using the decay law, then calculated activity using ( A = \lambda N ). Always check if the question asks for remaining nuclei or activity.
Problem: Calculate the binding energy per nucleon for ( ^{16}_8O ). Given: - Mass of ( ^{16}_8O ) = 15.994915 u - Mass of proton = 1.007276 u - Mass of neutron = 1.008665 u
Step 1: Identify problem type → Binding energy. Step 2: Given: - ( Z = 8 ), ( A = 16 ) - ( M_{\text{nucleus}} = 15.994915 ) u - ( m_p = 1.007276 ) u - ( m_n = 1.008665 ) u Step 3: Calculate mass defect: - ( \Delta m = Zm_p + (A-Z)m_n - M_{\text{nucleus}} ) - ( \Delta m = 8(1.007276) + 8(1.008665) - 15.994915 ) - ( \Delta m = 8.058208 + 8.06932 - 15.994915 = 0.132613 ) u Step 4: Convert to energy: - ( BE = \Delta m \times 931.5 ) MeV/u - ( BE = 0.132613 \times 931.5 = 123.56 ) MeV Step 5: Binding energy per nucleon: - ( \frac{BE}{A} = \frac{123.56}{16} = 7.72 ) MeV/nucleon
What we did and why: We calculated the mass defect first, then converted it to energy using ( 1 \text{ u} = 931.5 \text{ MeV} ). Always divide by A for binding energy per nucleon.
MISTAKE: Using ( t_{1/2} ) directly in ( N = N_0 e^{-\lambda t} ) without converting to ( \lambda ). WHY IT HAPPENS: Confusing half-life with decay constant. CORRECT APPROACH: Always use ( \lambda = \frac{0.693}{t_{1/2}} ) first.
MISTAKE: Forgetting to convert mass defect to kg before using ( E = mc^2 ). WHY IT HAPPENS: Using u (atomic mass units) directly in ( E = mc^2 ). CORRECT APPROACH: Convert u to kg (1 u = 1.66 × 10⁻²⁷ kg) or use 931.5 MeV/u.
MISTAKE: Mixing up activity (A) and number of nuclei (N). WHY IT HAPPENS: Not distinguishing between ( A = \lambda N ) and ( N = N_0 e^{-\lambda t} ). CORRECT APPROACH: Activity is decays per second, not remaining nuclei.
MISTAKE: Incorrectly balancing nuclear equations (e.g., forgetting neutrons in fission). WHY IT HAPPENS: Not checking mass and atomic numbers on both sides. CORRECT APPROACH: Ensure ( \Sigma A ) and ( \Sigma Z ) are equal on both sides.
MISTAKE: Using wrong units for time (e.g., years instead of seconds). WHY IT HAPPENS: Not converting to consistent units. CORRECT APPROACH: Always use seconds for ( \lambda ) and ( t ).
TRAP: Giving half-life in years but asking for decay constant in s⁻¹. HOW TO SPOT IT: Question mentions "per second" but gives time in years. HOW TO AVOID IT: Convert years to seconds (1 year = 3.15 × 10⁷ s).
TRAP: Asking for binding energy per nucleon but only giving total binding energy. HOW TO SPOT IT: Question says "per nucleon" but gives BE in MeV. HOW TO AVOID IT: Always divide by A (mass number).
TRAP: Fission/fusion questions with missing mass values (e.g., "energy released" but no masses given). HOW TO SPOT IT: No mass defect provided, but energy is asked. HOW TO AVOID IT: Use mass-energy equivalence (1 u = 931.5 MeV) and balance the equation first.
"Listen up—this is your 60-second nuclei crash course for NEET.
Radioactive decay? Use ( N = N_0 e^{-\lambda t} ). Half-life? ( t_{1/2} = \frac{0.693}{\lambda} ). Activity? ( A = \lambda N ). Memorise these three.
Binding energy? Find mass defect first: ( \Delta m = Zm_p + (A-Z)m_n - M_{\text{nucleus}} ). Then ( BE = \Delta m \times 931.5 ) MeV. Divide by A for per nucleon.
Fission/fusion? Balance the equation. Mass lost? Convert to energy with ( E = \Delta m \cdot c^2 ).
Units matter! Time in seconds, mass in kg or u, energy in MeV. 1 u = 931.5 MeV.
Common traps? Half-life in years? Convert to seconds. Asking for per nucleon? Divide by A. No masses given? Balance the equation first.
You’ve got this. Now go ace those 10-12 marks!
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