By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Hydrohalogenation is the addition of a hydrogen halide (HX, where X is a halogen like Cl, Br, or I) to an alkene or alkyne, resulting in the formation of a haloalkane. This topic is crucial for exams because it tests your understanding of organic reaction mechanisms, carbocation stability, and rearrangements. Questions typically involve predicting products, explaining mechanisms, and identifying rearrangements.
Hydrohalogenation is tested in organic chemistry exams, particularly in undergraduate and graduate-level courses. It frequently appears in midterm and final exams, carrying moderate to high marks. This topic tests your ability to understand and apply reaction mechanisms, a fundamental skill in organic chemistry.
Without these, you'll struggle to follow the mechanisms and predict products.
Hydrohalogenation follows Markovnikov's Rule: The hydrogen from HX adds to the carbon with more hydrogens, and the halogen adds to the carbon with fewer hydrogens.
Remember the mnemonic "H to More, X to Less" for Markovnikov's Rule.
Intermediate
Question: Predict the major product of the reaction between 2-methylpropene and HCl.
Step-by-Step:1. Identify the more substituted carbon (tertiary carbon).2. Apply Markovnikov's Rule: H adds to the less substituted carbon, Cl adds to the more substituted carbon.3. The major product is 2-chloro-2-methylpropane.
Answer: 2-chloro-2-methylpropane
Question: Explain the mechanism of the reaction between 2-methylbut-2-ene and HBr.
Step-by-Step:1. Protonation of the alkene forms a tertiary carbocation.2. The carbocation can rearrange to a more stable tertiary carbocation.3. The bromide ion attacks the carbocation to form the product.
Answer: The product is 2-bromo-2-methylbutane.
Question: Predict the products of the reaction between 3-methylpent-2-ene and HI, considering possible rearrangements.
Step-by-Step:1. Protonation forms a secondary carbocation.2. The carbocation rearranges to a tertiary carbocation.3. The iodide ion attacks the carbocation to form the product.
Answer: The product is 2-iodo-2-methylpentane.
Correct Approach: Always check for possible rearrangements.
Misapplying Markovnikov's Rule: Adding H to the more substituted carbon.
Correct Approach: Remember "H to More, X to Less."
Overlooking Carbocation Stability: Not recognizing the most stable carbocation.
Favored By: Undergraduate organic chemistry exams.
Short Answer: Explain the mechanism of a given reaction.
Favored By: Graduate-level organic chemistry exams.
Mechanism Drawing: Draw the complete mechanism, including all intermediates.
Question: What is the major product of the reaction between 2-methylpropene and HBr? - A: 1-bromo-2-methylpropane - B: 2-bromo-2-methylpropane - C: 1-bromopropane - D: 2-bromopropane
Correct Answer: B, 2-bromo-2-methylpropane
Explanation: Markovnikov's Rule predicts that H adds to the less substituted carbon and Br adds to the more substituted carbon.
Why the Distractors Are Tempting: - A: Incorrect regiochemistry. - C: Incorrect compound. - D: Incorrect regiochemistry.
Question: Which of the following is the major product of the reaction between but-2-ene and HCl? - A: 1-chlorobutane - B: 2-chlorobutane - C: 1-chloro-2-methylpropane - D: 2-chloro-2-methylpropane
Correct Answer: B, 2-chlorobutane
Explanation: Markovnikov's Rule predicts that H adds to the less substituted carbon and Cl adds to the more substituted carbon.
Why the Distractors Are Tempting: - A: Incorrect regiochemistry. - C: Incorrect compound. - D: Incorrect compound.
Question: What is the major product of the reaction between 2-methylbut-2-ene and HI? - A: 2-iodo-2-methylbutane - B: 3-iodo-2-methylbutane - C: 1-iodobutane - D: 2-iodobutane
Correct Answer: A, 2-iodo-2-methylbutane
Explanation: Markovnikov's Rule predicts that H adds to the less substituted carbon and I adds to the more substituted carbon.
Why the Distractors Are Tempting: - B: Incorrect regiochemistry. - C: Incorrect compound. - D: Incorrect compound.
Question: Which of the following is NOT a possible product of the reaction between 3-methylpent-2-ene and HBr? - A: 2-bromo-3-methylpentane - B: 2-bromo-2-methylpentane - C: 3-bromo-3-methylpentane - D: 1-bromo-3-methylpentane
Correct Answer: D, 1-bromo-3-methylpentane
Explanation: Markovnikov's Rule and carbocation rearrangements do not support this product.
Why the Distractors Are Tempting: - A: Possible product. - B: Possible product. - C: Possible product.
Question: What is the major product of the reaction between pent-2-ene and HI? - A: 2-iodopentane - B: 3-iodopentane - C: 1-iodopentane - D: 2-iodo-2-methylbutane
Correct Answer: A, 2-iodopentane
Why the Distractors Are Tempting: - B: Incorrect regiochemistry. - C: Incorrect regiochemistry. - D: Incorrect compound.
Join 4M+ learners. Unlock unlimited quizzes, wrong-answer tracking, flashcards + reminders, study guides, and 1-on-1 challenges.