By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Hybridisation is the process by which atomic orbitals combine to form new molecular orbitals, resulting in the formation of a molecule. This is a fundamental concept in chemistry that helps us understand the structure and properties of molecules.
This topic appears in exams to test your understanding of the underlying principles of molecular structure and how they relate to the properties of molecules. You can expect questions on the types of hybridisation, bond lengths, and strengths.
This topic is frequently tested in exams, particularly in chemistry and related fields. It typically carries a significant portion of the total marks, around 20-30%. The examiner is testing your ability to apply the principles of hybridisation to predict the structure and properties of molecules.
To tackle questions on hybridisation, you need to understand the following foundational ideas:
Before tackling this topic, you need to have a solid understanding of:
The primary rule of hybridisation is:
Sub-rules and exceptions include:
A simple visual pattern to remember is:
Frequency: 60% Difficulty Rating: Intermediate Question Type or Real-World Task Type: Multiple-choice questions, short-answer questions, and essay questions.
Intermediate
The following are the most important rules and formulas to remember:
Here are three worked examples that escalate in difficulty:
What is the hybridisation of the carbon atom in methane (CH?)?
Answer: sp³
What is the bond angle of the carbon atom in ethene (C?H?)?
Answer: 120°
What is the hybridisation of the carbon atom in benzene (C?H?)?
Answer: sp²
Here are four common mistakes that can cost marks in exams:
Here are some practical techniques to solve questions faster or more accurately under time pressure:
Here are the four distinct question formats that this topic appears in across different exams:
Here are five multiple-choice questions at mixed difficulty levels:
A) sp B) sp² C) sp³ D) d²sp³
Correct Answer: C) sp³ Explanation: The carbon atom has four valence electrons, which are involved in bonding. The number of hybrid orbitals is equal to the number of atomic orbitals involved. Therefore, the carbon atom undergoes sp³ hybridisation.
A) 90° B) 120° C) 109.5° D) 180°
Correct Answer: B) 120° Explanation: The carbon atom has three valence electrons, which are involved in bonding. The number of hybrid orbitals is equal to the number of atomic orbitals involved. Therefore, the carbon atom undergoes sp² hybridisation. The bond angle is determined by the number of hybrid orbitals.
Correct Answer: B) sp² Explanation: The carbon atom has four valence electrons, which are involved in bonding. However, the carbon atom is bonded to three other carbon atoms, which are also bonded to each other. Therefore, the carbon atom undergoes sp² hybridisation, with some degree of delocalisation.
What is the bond strength of a carbon-carbon bond in a molecule that undergoes sp³ hybridisation?
A) Weak B) Medium C) Strong D) Very strong
Correct Answer: B) Medium Explanation: The bond strength of a carbon-carbon bond is determined by the type of hybridisation. In a molecule that undergoes sp³ hybridisation, the bond strength is medium.
What is the hybridisation of the carbon atom in acetylene (C?H?)?
Correct Answer: A) sp Explanation: The carbon atom has two valence electrons, which are involved in bonding. The number of hybrid orbitals is equal to the number of atomic orbitals involved. Therefore, the carbon atom undergoes sp hybridisation.
Here are the five things you need to remember walking into the exam hall:
Here is a suggested study sequence to master this topic from scratch to exam-ready:
Here are three closely connected topics that appear alongside this one in exams:
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