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Solving Exponential Equations – Same Base and Logarithms
Solving exponential equations with the same base is a fundamental concept in algebra that allows us to find the value of the variable in an equation of the form $a^x = b$, where $a$ is the base and $b$ is the result of raising $a$ to some power $x$. This technique is used extensively in various fields, including science, engineering, economics, and data analysis.
Exponential equations with the same base appear in many real-world contexts, such as: - Population growth models in biology and ecology, where the population size grows exponentially over time. - Compound interest calculations in finance, where the interest earned is compounded at a fixed rate over a certain period. - Chemical reactions in chemistry, where the concentration of a substance changes exponentially over time.
An exponential function is a function of the form $f(x) = a^x$, where $a$ is the base and $x$ is the variable. The graph of an exponential function is a curve that increases or decreases exponentially as $x$ changes.
A same base exponential equation is an equation of the form $a^x = b$, where $a$ is the base and $b$ is the result of raising $a$ to some power $x$. To solve this equation, we need to find the value of $x$ that satisfies the equation.
A logarithmic function is the inverse of an exponential function. It is a function of the form $f(x) = \log_a x$, where $a$ is the base and $x$ is the variable. The logarithmic function returns the power to which the base must be raised to obtain the given value.
There are several important properties of logarithmic functions, including: - $\log_a (xy) = \log_a x + \log_a y$ - $\log_a (\frac{x}{y}) = \log_a x - \log_a y$ - $\log_a x^y = y \log_a x$
To solve a same base exponential equation, follow these steps:
Solve the equation $2^x = 16$.
$$ \begin{align} 2^x &= 16 \ \log_2 (2^x) &= \log_2 16 \ x &= \log_2 16 \ x &= 4 \end{align} $$
$x = 4$
The solution $x = 4$ means that $2^4 = 16$.
Solve the equation $3^x = 81$.
$$ \begin{align} 3^x &= 81 \ \log_3 (3^x) &= \log_3 81 \ x &= \log_3 81 \ x &= 4 \end{align} $$
The solution $x = 4$ means that $3^4 = 81$.
Solve the equation $4^x = 256$.
$$ \begin{align} 4^x &= 256 \ \log_4 (4^x) &= \log_4 256 \ x &= \log_4 256 \ x &= 4 \end{align} $$
The solution $x = 4$ means that $4^4 = 256$.
Solve the equation $2^x = 32$.
A) $x = 2$ B) $x = 3$ C) $x = 4$ D) $x = 5$
C) $x = 4$
The solution $x = 4$ means that $2^4 = 32$.
The distractors are tempting because they are plausible solutions, but they are not correct.
Solve the equation $3^x = 243$.
A) $x = 3$ B) $x = 4$ C) $x = 5$ D) $x = 6$
C) $x = 5$
The solution $x = 5$ means that $3^5 = 243$.
Solve the equation $4^x = 1024$.
The solution $x = 4$ means that $4^4 = 1024$.
To master solving exponential equations, follow this learning path:
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