By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
A geometric sequence is a sequence of numbers where each term after the first is found by multiplying the previous term by a fixed, non-zero number called the common ratio. This concept is crucial in understanding patterns and growth in various fields, such as finance, biology, and physics.
Geometric sequences appear in many real-world applications, including: * Compound interest calculations in finance, where the common ratio represents the interest rate. * Population growth models in biology, where the common ratio represents the growth rate. * Signal processing in engineering, where geometric sequences are used to model and analyze signals.
A geometric sequence is a sequence of numbers ${a_n}$ where each term $a_n$ is given by:
$$a_n = a_1 \cdot r^{n-1}$$
where $a_1$ is the first term, $r$ is the common ratio, and $n$ is the term number.
The common ratio $r$ is the ratio of any term to its previous term. It is a fixed, non-zero number that determines the growth or decay of the sequence.
The nth term of a geometric sequence can be found using the formula:
$$a_1 = 2, r = 3, n = 5$$
$$a_5 = a_1 \cdot r^{n-1} = 2 \cdot 3^{5-1} = 2 \cdot 3^4 = 2 \cdot 81 = 162$$
$$a_1 = 5, a_{10} = 125$$
$$a_{10} = a_1 \cdot r^{10-1} = 5 \cdot r^9$$
$$125 = 5 \cdot r^9$$
$$r^9 = 25$$
$$r = 5^{2/9}$$
$$a_5 = 64, r = 2$$
$$a_5 = a_1 \cdot r^{5-1} = a_1 \cdot 2^4 = 64$$
$$a_1 \cdot 16 = 64$$
$$a_1 = 4$$
What is the formula for the nth term of a geometric sequence?
A) $a_n = a_1 \cdot r^{n-1}$ B) $a_n = r \cdot a_{n-1}$ C) $a_n = a_1 + r^{n-1}$ D) $a_n = a_1 - r^{n-1}$
A) $a_n = a_1 \cdot r^{n-1}$
The formula for the nth term of a geometric sequence is $a_n = a_1 \cdot r^{n-1}$, where $a_1$ is the first term and $r$ is the common ratio.
What is the common ratio of a geometric sequence with first term 3 and 5th term 243?
A) 2 B) 3 C) 4 D) 5
B) 3
The common ratio of a geometric sequence can be found by dividing the 5th term by the first term: $r = \frac{a_5}{a_1} = \frac{243}{3} = 81^{1/4} = 3$.
What is the first term of a geometric sequence with 5th term 32 and common ratio 2?
A) 4 B) 8 C) 16 D) 32
B) 8
The first term of a geometric sequence can be found by dividing the 5th term by the common ratio raised to the power of 4: $a_1 = \frac{a_5}{r^4} = \frac{32}{2^4} = \frac{32}{16} = 2$.
To master geometric sequences, follow this learning path:
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