By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Adding and subtracting rational expressions involves combining or comparing fractions with polynomials in the numerator and denominator. This process is crucial in algebra and calculus, particularly when simplifying expressions and solving equations.
In real-world applications, adding and subtracting rational expressions appears in various fields, such as: * Data analysis: When comparing rates of change or combining probabilities. * Science: In physics, chemistry, and engineering, where rational expressions represent proportions or ratios of quantities. * Economics: When modeling economic systems, rational expressions represent ratios of costs, revenues, or quantities.
A rational expression is a fraction whose numerator and denominator are polynomials.
$$\frac{p(x)}{q(x)}$$
where $p(x)$ and $q(x)$ are polynomials.
To add or subtract rational expressions, we need a common denominator, which is the least common multiple (LCM) of the denominators.
The LCM of two or more polynomials is the smallest polynomial that is a multiple of each of the given polynomials.
Determine the rational expressions involved in the problem.
Determine the LCM of the denominators.
Rewrite each rational expression with the common denominator.
Add or subtract the numerators, leaving the common denominator unchanged.
Simplify the resulting rational expression, if possible.
Add $\frac{x+2}{x^2+4x+4}$ and $\frac{x-3}{x^2+4x+4}$.
$$\begin{aligned} \frac{x+2}{x^2+4x+4} + \frac{x-3}{x^2+4x+4} &= \frac{(x+2) + (x-3)}{x^2+4x+4} \ &= \frac{2x-1}{x^2+4x+4} \end{aligned}$$
$\boxed{\frac{2x-1}{x^2+4x+4}}$
Subtract $\frac{x-2}{x^2+3x+2}$ from $\frac{x+4}{x^2+3x+2}$.
$$\begin{aligned} \frac{x+4}{x^2+3x+2} - \frac{x-2}{x^2+3x+2} &= \frac{(x+4) - (x-2)}{x^2+3x+2} \ &= \frac{6}{x^2+3x+2} \end{aligned}$$
$\boxed{\frac{6}{x^2+3x+2}}$
Add $\frac{x+1}{x^2-4}$ and $\frac{2x-3}{x^2-4}$, then subtract $\frac{x-2}{x^2-4}$.
$$\begin{aligned} \frac{x+1}{x^2-4} + \frac{2x-3}{x^2-4} - \frac{x-2}{x^2-4} &= \frac{(x+1) + (2x-3) - (x-2)}{x^2-4} \ &= \frac{2x}{x^2-4} \end{aligned}$$
$\boxed{\frac{2x}{x^2-4}}$
What is the common denominator of $\frac{x+2}{x^2+4x+4}$ and $\frac{x-3}{x^2+4x+4}$?
A) $x^2+4x+4$ B) $x^2+4x+3$ C) $x^2+4x+5$ D) $x^2+4x+2$
A) $x^2+4x+4$
The LCM of $x^2+4x+4$ and $x^2+4x+4$ is $x^2+4x+4$.
B) $x^2+4x+3$ is a plausible distractor because it is close to the correct answer, but it is not the LCM of the denominators. C) $x^2+4x+5$ is a plausible distractor because it is a larger polynomial, but it is not the LCM of the denominators. D) $x^2+4x+2$ is a plausible distractor because it is a smaller polynomial, but it is not the LCM of the denominators.
A) $\frac{2x-1}{x^2+4x+4}$ B) $\frac{2x+1}{x^2+4x+4}$ C) $\frac{2x-3}{x^2+4x+4}$ D) $\frac{2x+3}{x^2+4x+4}$
A) $\frac{2x-1}{x^2+4x+4}$
The correct answer is $\frac{2x-1}{x^2+4x+4}$ because we added the numerators and left the common denominator unchanged.
B) $\frac{2x+1}{x^2+4x+4}$ is a plausible distractor because it is close to the correct answer, but it is not the correct result of adding the numerators. C) $\frac{2x-3}{x^2+4x+4}$ is a plausible distractor because it is a plausible result of adding the numerators, but it is not the correct result. D) $\frac{2x+3}{x^2+4x+4}$ is a plausible distractor because it is a plausible result of adding the numerators, but it is not the correct result.
A) $\frac{6}{x^2+3x+2}$ B) $\frac{4}{x^2+3x+2}$ C) $\frac{2}{x^2+3x+2}$ D) $\frac{8}{x^2+3x+2}$
A) $\frac{6}{x^2+3x+2}$
The correct answer is $\frac{6}{x^2+3x+2}$ because we subtracted the numerators and left the common denominator unchanged.
B) $\frac{4}{x^2+3x+2}$ is a plausible distractor because it is close to the correct answer, but it is not the correct result of subtracting the numerators. C) $\frac{2}{x^2+3x+2}$ is a plausible distractor because it is a plausible result of subtracting the numerators, but it is not the correct result. D) $\frac{8}{x^2+3x+2}$ is a plausible distractor because it is a plausible result of subtracting the numerators, but it is not the correct result.
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