By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
Chemical Kinetics is a crucial topic in JEE, appearing in 2-3 questions every year, mainly in the Chemistry section. It's a moderate difficulty topic, with a slightly higher weightage for JEE Advanced. Understanding the basics of activation energy, Arrhenius equation, and catalysis mechanisms is essential for solving problems accurately and quickly.
If you're new to these topics, focus on understanding the basics of chemical equilibrium and thermodynamics. Brush up on chemical reactions, especially the types and examples.
The Arrhenius plot is a common graph, showing the relationship between the rate constant (k) and temperature (T). Examiners test the slope and intercept of this plot.
Exam board insight: Examiners penalize this mistake by awarding zero marks.
The mistake: Ignoring the catalyst in the reaction.
Question 1: A reaction has an activation energy of 10 kJ/mol. What is the minimum temperature (T) required for the reaction to occur, given that the equilibrium constant (K) is 10?
A) 300 K B) 350 K C) 400 K D) 500 K
Answer: B) 350 K Solution: Use the Arrhenius equation: Ea = RT ln(K). Rearrange to find T: T = Ea / (R ln(K)). Plug in the values: T = 10 kJ/mol / (8.314 J/mol K ln(10)). Simplify to get T = 350 K. Common Wrong Answer: A) 300 K, because the student forgot to use the equilibrium constant (K).
Question 2: A catalyst is added to a reaction, and the rate constant (k) increases by a factor of 10. What is the effect on the activation energy (Ea)?
A) Decreases by a factor of 10 B) Decreases by a factor of 2 C) Remains the same D) Increases by a factor of 10
Answer: A) Decreases by a factor of 10 Solution: Use the Arrhenius equation: k = Ae^(-Ea/RT). Since the rate constant (k) increases by a factor of 10, the activation energy (Ea) must decrease by a factor of 10. Common Wrong Answer: D) Increases by a factor of 10, because the student forgot that the catalyst lowers the activation energy.
Question 3: A reaction has a rate constant (k) of 10^-3 s^-1 at a temperature of 300 K. What is the activation energy (Ea) of the reaction?
A) 10 kJ/mol B) 20 kJ/mol C) 30 kJ/mol D) 40 kJ/mol
Answer: B) 20 kJ/mol Solution: Use the Arrhenius equation: k = Ae^(-Ea/RT). Rearrange to find Ea: Ea = -RT ln(k/A). Plug in the values: Ea = -8.314 J/mol K * 300 K * ln(10^-3 s^-1). Simplify to get Ea = 20 kJ/mol. Common Wrong Answer: A) 10 kJ/mol, because the student forgot to use the correct units for the rate constant (k).
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